The acceleration of the ball is 9.8 m/s^2, which is due to gravity acting on it.
The acceleration of the sepaktakraw ball after 1 second will be approximately 9.81 m/s^2, assuming the ball is under the influence of gravity. This is the acceleration due to gravity acting downwards on the ball.
The acceleration of the ball is about 9.8 m/s^2, which is the acceleration due to gravity.
When a ball increases in speed by the same amount each second, its acceleration is constant. This type of motion is known as constant acceleration.
Ignoring air resistance, the acceleration is constant, from the moment the ballleaves the hand until the moment it hits the ground, regardless of the mass ofthe ball or the height from which it's released.It's 9.8 meters (32.2 feet) per second2 . That's the acceleration of gravity. (On Earth.)The speed of a dropped object grows continuously. At the end of 1 second,it's 9.8 meters (32.2 feet) per second.
The acceleration of the ball can be calculated using Newton's second law, which states that acceleration is equal to the force applied divided by the mass of the object. In this case, the acceleration would be 25 N divided by the mass of the ball in kg.
The acceleration of the sepaktakraw ball after 1 second will be approximately 9.81 m/s^2, assuming the ball is under the influence of gravity. This is the acceleration due to gravity acting downwards on the ball.
The acceleration of the ball is about 9.8 m/s^2, which is the acceleration due to gravity.
When a ball increases in speed by the same amount each second, its acceleration is constant. This type of motion is known as constant acceleration.
Approx 9.8 metres per second^2, downwards.
Ignoring air resistance, the acceleration is constant, from the moment the ballleaves the hand until the moment it hits the ground, regardless of the mass ofthe ball or the height from which it's released.It's 9.8 meters (32.2 feet) per second2 . That's the acceleration of gravity. (On Earth.)The speed of a dropped object grows continuously. At the end of 1 second,it's 9.8 meters (32.2 feet) per second.
The acceleration of the ball can be calculated using Newton's second law, which states that acceleration is equal to the force applied divided by the mass of the object. In this case, the acceleration would be 25 N divided by the mass of the ball in kg.
The acceleration of the ball would depend on its mass and the force of the push. This is because force = mass times acceleration. You could manipulate this equation to solve for acceleration by dividing each side by mass. Acceleration therefore equals force/mass.
Using Newton's second law (F=ma), the acceleration of the ball can be calculated by dividing the force (25 N) by the mass of the ball (0.3 kg). The acceleration of the ball would be 83.3 m/s^2.
The acceleration of the ball at that moment would be approximately equal to the acceleration due to gravity, which is about 9.81 m/s^2. This acceleration is acting downward towards the ground, assuming no other forces are acting on the ball.
No. When the ball falls, there are two forces acting on it; one is the gravitational force and the other air resistance, which is dependant on speed. At the point it is released. Its instantaneous speed is 0m/s The next second, 10m/s, (result of acceleration). the ball will undergo decreasing acceleration. Thus the distance it falls each second is different.
In a vacuum, like the moon, the acceleration due to gravity is about 9.8 meters per second squared, so each second the speed of the ball increases by 9.8 meters per second. On Earth, with air resistance, the acceleration due to gravity is about 9.81 meters per second squared.
F = m A = (1 kg) x (1 m/s2) = 1 kg-m/s2 = 1 newton