Ignoring air resistance, the acceleration is constant, from the moment the ball
leaves the hand until the moment it hits the ground, regardless of the mass of
the ball or the height from which it's released.
It's 9.8 meters (32.2 feet) per second2 . That's the acceleration of gravity. (On Earth.)
The speed of a dropped object grows continuously. At the end of 1 second,
it's 9.8 meters (32.2 feet) per second.
Both balls would have the same acceleration due to gravity, regardless of the height from which they were dropped. This is because the acceleration due to gravity is constant and does not depend on the initial position of the objects.
The acceleration of the ball is 9.8 m/s^2, which is due to gravity acting on it.
The acceleration of the sepaktakraw ball after 1 second will be approximately 9.81 m/s^2, assuming the ball is under the influence of gravity. This is the acceleration due to gravity acting downwards on the ball.
When a ball increases in speed by the same amount each second, its acceleration is constant. This type of motion is known as constant acceleration.
If air resistance can be neglected, the acceleration of a ball tossed straight upward is the same as when it is dropped - both experience a gravitational acceleration of 9.81 m/s^2 downward. The initial velocity of the tossed ball would cause it to momentarily counteract the acceleration and then eventually slow down and reverse direction due to gravity.
Yes.
Both balls would have the same acceleration due to gravity, regardless of the height from which they were dropped. This is because the acceleration due to gravity is constant and does not depend on the initial position of the objects.
Same as the 15kg ball. 9.8m/sec^2.
Acceleration due to the force of gravity.
29.4/3=9.8m/s2
The acceleration of the ball is 9.8 m/s^2, which is due to gravity acting on it.
The acceleration of the sepaktakraw ball after 1 second will be approximately 9.81 m/s^2, assuming the ball is under the influence of gravity. This is the acceleration due to gravity acting downwards on the ball.
If we disregard air resistance; they both have identical acceleration under gravity. If we take air resistance into account, then the mass that is fired will be de-accelerating slightly, so if you calculate the overall acceleration it will be slightly lower than the mass that is dropped.
The factors that affect the bounce of a dropped ball include...... the height from which it is dropped; the force applied to it, if any, when dropped; the acceleration of gravity, which is different depending upon what planet you're on ; the elasticity of the ball; the density of the atmosphere, which affects "air resistance"; and the rigidity and elasticity of the surface on which the ball bounces.
When a ball increases in speed by the same amount each second, its acceleration is constant. This type of motion is known as constant acceleration.
If air resistance can be neglected, the acceleration of a ball tossed straight upward is the same as when it is dropped - both experience a gravitational acceleration of 9.81 m/s^2 downward. The initial velocity of the tossed ball would cause it to momentarily counteract the acceleration and then eventually slow down and reverse direction due to gravity.
The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.