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What is the answer of these problem a truck's velocity on a straight highway increases uniformly from 15 kmh to 60kmh in 20s. determine average speed in kph and mps the acceleration in mps nd distance?
Wiki User
∙ 11y ago
Average velocity in km/h
vavg = (v1 + v2)/2 = (15km/h + 60km/h)/2 = (75km/h)/2 = 37.5km/h
Average velocity in m/s
vavg = 37.5km/h x 1000m/km x 1h/3600s = 10.4m/s
Initial velocity in m/s
vi = 15km/h x 1000m/km x 1h/3600s = 4.2m/s
Final velocity in m/s
vf = 60km/h x 1000m/km x 1h/3600s = 17m/s
Acceleration in m/s2
a = (vf - vi)/Δt = (17m/s - 4.2m/s)/20s = 0.64m/s/s = 0.64m/s2
Displacement from initial velocity, acceleration, and time interval
d = vit + 1/2at2 = 4.2m/s x 20s + 1/2(0.64m/s2)(20s)2 = 212m
Wiki User
∙ 11y ago
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An object uniformly accelerates over a distance of 100 m in 20 seconds. What is the acceleration?
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
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5.0 meters every second.
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The slope increases.
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No, that won't do it. You need to divide the distance the object went by the time it took to go that distance.
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