6.512935123262767e-37 Joule
Found using eculator.
energy=hc/wave length
h=6.626x10-34joule.sec{planck's constant}
c=3x108 metres/sec
wavelength=3.35x10-7 meters
therefore answer=approximately 6x10-19 joules
35 nm= 35 x 10-9 m C=λv 3.00 x 108 m/s = 35 x 10-9 m (v) v= 8.6 x 1015 Hz E= hv E= 6.626 x 10-34 J (sec) x (8.6 x 1015 1/sec) E= 5.7 x 10-18 J
4.7 x 10 to the -19 J
The wavelength is 436 nm.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
Twice the energy means twice the frequency, and therefore half the wavelength.
89
The energy of the photon is 3,1631.e-19 joule.
The wavelength is 436 nm.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
Twice the energy means twice the frequency, and therefore half the wavelength.
The energy of the photon is 3,1631.e-19 joule.
89
Energy per photon is proportional to frequency. That tells us that it's alsoinversely proportional to wavelength.So if Photon-A has wavelength of 400-nm, then wavelength of Photon-Bwith twice as much energy is 200-nm .
610 nm
The wavelength is 610 nm.
The wavelength is 435,62 nm.
4.44 10-19 j
4.7*10^-19 j
4.44 10-19 j