251Cf --> 247Cm + 4He
247Cm --> 243Pu + 4He
243Pu --> 243Am + e-
243Am --> 239Np + 4He
239Np --> 239Pu + e-
239Pu --> 235U + 4He
235U --> 231Th + 4He
231Th --> 231Pa + e-
231Pa --> 227Ac + 4He
227Ac --> 223Fr + 4He, 227Th + e-
223Fr --> 219At + 4He, 223Ra + e-
227Th --> 223Ra + 4He
219At --> 215Bi + 4He, 219Rn + e-
223Ra --> 219Rn + 4He
215Bi --> 215Po + e-
219Rn --> 215Po + 4He
215Po --> 211Pb + 4He
211Pb --> 211Bi + e-
211Bi --> 207Tl + 4He, 211Po + e-
207Tl --> 207Pb + e-
211Po --> 207Pb + 4He
207Pb: stable
Lead-210 decays by alpha or beta decay. The equation for the alpha decay of 210Pb is: 82210Pb --> 80206Hg + 24He representing the alpha particle as a helium nucleus. The equation for the beta decay of 210Pb is: 82210Pb --> 83210Bi + -10e where the -10e is an electron.
The muon decay equation is: - e- e . This equation describes the process of muon decay, where a muon (-) transforms into an electron (e-), an electron neutrino (e), and a muon neutrino (). This decay process occurs due to the weak nuclear force, which causes the muon to change into lighter particles.
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
The equation for the beta decay of 86Rb:3786Rb --> 3886Sr+ -10e where the -10e represents a beta particle or electron.
When californium-251 decays into curium-247, it undergoes alpha decay, releasing an alpha particle (helium nucleus) in the process. This results in the transformation of the nucleus to curium-247 with a simultaneous decrease in atomic number and mass number.
The atomic number of californium is 98. The atomic mass of the most stable isotope - 251Cf - is (251) after IUPAC.
251.
All the isotopes of californium are radioactive, artificial and unstable.
Californium, with the chemical symbol Cf, is the chemical element with the atomic number 98.
The atomic number of californium is 98. The atomic mass of the most stable isotope - 251Cf - is (251) after IUPAC.
Because californium is an unstable, radioactive chemical element disappear by radioactive decay.
For the first time californium is obtained with the nuclear reaction:Cm-242 + He--------------Cf-245 + nThe important isotope Cf-252 is obtained in nuclear reactors after a long time irradiation of plutonium with neutrons.
It emits a "beta particle," which is simply an electron. Cf-251's nucleus contains 153 neutrons. One of them spontaneously becomes a proton and an electron. The new proton bumps up its atomic number by 1, so it becomes Es-251. The overall mass is unchanged. The electron, or beta particle, is ejected from the nucleus. This is called beta decay.
Being radioactive californium is unstable.
Each isotope has another type of decay but generally from californium are formed curium isotopes and an alpha particle.
Californium, Symbol: Cf, Atomic Number: 98, Atomic Weight: 251