If the planet is a hollow shell, of any thickness but with a hole in the middle,
and the material in the shell is evenly distributed (homogeneous, or of uniform
density), then there is zero gravity anywhere inside the shell.
it's zero
The electric FIELD inside a charged hollow CONDUCTOR is zero.
By keeping it inside in a hollow conducting sphere. This process is known as electrostatic shielding.
If the net charge enclosed by a surface is zero then the field at all points on the surface is not zero because gauss's law states that if the charge enclosed by a surface is zero then the flux through the surface is zero which depends upon the magnitude of field and the angle that it makes with the area vector at each point and so it is not necessary that the field will be zero at all points of the surface.
If the charge is evenly distributed over the sphere ... as it would be if the sphere is a conducting material ... then the electric field at the center of the sphere is zero. If the sphere is not a conductor and the charge hasn't been applied to it symmetrically, then the magnitude and direction of the electric field at the center depend on every little detail of exactly how it's distributed on the sphere.
To eleminate stray electrical field interference, circuits of sensitive electronic devices such as TV and Computers are often enclosed within metal boxes. According to Gauss's law the intensity of the field inside a hollow chart sphere is 0.
The electric FIELD inside a charged hollow CONDUCTOR is zero.
It is zero.
By keeping it inside in a hollow conducting sphere. This process is known as electrostatic shielding.
If the net charge enclosed by a surface is zero then the field at all points on the surface is not zero because gauss's law states that if the charge enclosed by a surface is zero then the flux through the surface is zero which depends upon the magnitude of field and the angle that it makes with the area vector at each point and so it is not necessary that the field will be zero at all points of the surface.
Sounds like a star, but it is nuclear fusion there, not fission A planet is held together by its gravitational field and there is nuclear FISSION going on inside it producing geothermal heat.
If the charge is evenly distributed over the sphere ... as it would be if the sphere is a conducting material ... then the electric field at the center of the sphere is zero. If the sphere is not a conductor and the charge hasn't been applied to it symmetrically, then the magnitude and direction of the electric field at the center depend on every little detail of exactly how it's distributed on the sphere.
A star.
a "star"
To eleminate stray electrical field interference, circuits of sensitive electronic devices such as TV and Computers are often enclosed within metal boxes. According to Gauss's law the intensity of the field inside a hollow chart sphere is 0.
Yes. If the sphere is homogeneous ... meaning that every speck of it has the same mass, density, etc. ... then it turns out that at any point inside the sphere, all the mass outside that radius cancels out. The sphere acts as if the outside part doesn't exist, and the gravitational field is what you'd expect from only the part of the sphere that's inside that radius.
Are you kidding me? Its zero. That's the easiest E/m question ever. because: A: Every textbook talks ad nauseum about how the field inside any solid conductor or hollow conduction is zero B. The problem doesn't give you any numbers about how large the negative charge is. If you weren't an idiot you should see that you can't actually come up with any sort of numerical answer unless its infinity or zero. Since an infinite electric field on the inside is not physical, it must be zero. Read your book sometime- It would help. What is the mathematical solution to the problem?
electric field inside the conducting sphere is ZER0..! because their are equivalent charges all around the sphere which makes the net force zero hence we can say that the electric field is also zero.!