3.3 Joule (it follows the equation: Heat loss=mass*specific heat*temp. difference)
You are supposed to divide the energy by the product of (mass x temperature difference).
The heat lost can be calculated using the formula Q = mcΔT, where Q is the heat lost, m is the mass of the copper (640g), c is the specific heat capacity of copper (0.385 J/g°C), and ΔT is the change in temperature (375°C - 26°C = 349°C). Plugging in these values, the heat lost is 640g * 0.385 J/g°C * 349°C = 85,688 J or 85.7 kJ.
To calculate the energy transferred when heating copper, you can use the formula: Energy = mass * specific heat capacity * temperature change. The specific heat capacity of copper is 0.385 J/g°C. Plugging in the values, you get: Energy = 3kg * 0.385 J/g°C * (220°C - 20°C).
Substances with low specific heat have the ability to heat up or cool down quickly with a small amount of energy. Common examples include metals like copper and aluminum, which have low specific heat compared to substances like water.
Substances with low specific heat capacity include metals like aluminum and copper, as well as gases like helium and hydrogen. These substances heat up and cool down quickly compared to substances with higher specific heat capacities.
The specific heat of copper at standard temperature and pressure (STP) is approximately 0.385 J/g°C. This means that it requires 0.385 joules of energy to raise the temperature of 1 gram of copper by 1 degree Celsius at STP.
The specific heat capacity of copper sulfate varies with temperature. At room temperature, it is approximately 0.39 J/g°C.
If a person ties a piece of copper wire at the end of the exhaust pipe on a vehicle the copper is going to heat up. When the copper heats up it will turn a rainbow of colors.
The specific heat of copper(II) sulfate is approximately 0.39 J/g°C. This value represents the amount of heat required to raise the temperature of 1 gram of copper(II) sulfate by 1°C.
To calculate the heat energy required, you can use the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the copper (0.365 kg), c is the specific heat capacity of copper (0.0920 J/g°C), and ΔT is the change in temperature (60.0°C - 23.0°C). First, convert the mass to grams and then plug the values into the formula to find the heat energy required.
Water has a greater specific heat capacity than copper. This means that water can absorb more heat energy before its temperature increases compared to copper. This property of water is why it is often used as a coolant in various applications.
The specific heat of copper is 0.093 cal/g(C°) or 390 J/kg(C°).
The specific heat capacity of copper is approximately 0.385 J/g°C. This means that it takes 0.385 joules of energy to raise the temperature of 1 gram of copper by 1 degree Celsius. Copper has a relatively high specific heat capacity compared to other metals.
The specific heat of water is 4184 J kg-1 K-1 The specific heat of copper 385 J kg-1 K-1. So the answer is no.
The copper wire will undergo the fastest increase in temperature because it has a lower specific heat capacity compared to aluminum. This means copper can absorb heat more quickly and reach a higher temperature faster than aluminum when exposed to the same amount of heat.
The specific heat capacity of copper is 0.385 J/g°C. You can use the formula Q = mcΔT, where Q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, you can calculate the heat absorbed by the copper.
These are not temperature numbers but specific heat numbers. They mean that it takes 4.184 Joules and 0.387 Joules respectively to raise water and copper of one gram by one degree celsius. So, as you can see, it takes a lot more heat to raise the temperature of water than it does of copper. Water has a very high specific heat.