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The horizontal acceleration of a ball rolling off a cliff is typically considered to be zero, assuming air resistance is neglected. The force of gravity acting vertically downward does not contribute to horizontal acceleration, as the ball falls vertically due to gravity while maintaining its initial horizontal velocity.
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A ball is thrown horizontally from a cliff at a speed of 15 and strikes the ground 45 meters from the base of the cliff How high was the cliff?
Well, let's think about this together. The horizontal distance the ball travels is 45 meters, and we know the initial horizontal velocity is 15 m/s. Using the formula for horizontal distance, time, and velocity, we can calculate the time it takes for the ball to reach the ground. Then, we can use this time in the vertical motion formula to find the height of the cliff. Remember, mistakes are just happy accidents in the world of math!
Can a rock falling from a cliff have a constant acceleration?
Yes, a rock falling from a cliff will experience a constant acceleration due to gravity, which is approximately 9.8 m/s². Ignoring air resistance, the rock will continue to accelerate at this rate until it reaches the ground.
A ball is thrown horizontally from a cliff at a speed of 9 meters per second What is its speed one second later?
Ignoring air resistance, its horizontal speed is still 9 meters per second, its vertical speed is approx. 9.81 m/s, as the acceleration of gravity is 9.81 meters per second per second.
Does a rock falling from a cliff have a constant acceleration?
Yes. Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration. Mass does not affect the acceleration of the body. According to Newton's second law: F=m*a m*g=m*a g=a F= Force m= mass a= acceleration g= gravity acceleration m*g= the force of gravity
A person on a very high cliff throws a ball vertically up at an initial speed of 13.0 ms Neglect friction whats the speed at the highest point the acceleration at the highest point?
At the highest point, the speed of the ball is 0 m/s because it momentarily stops before falling back down. The acceleration at the highest point is equal to the acceleration due to gravity (approximately -9.8 m/s^2) acting in the downward direction.
A ball is thrown horizontally from a cliff at a speed of 15 and strikes the ground 45 meters from the base of the cliff How high was the cliff?
Well, let's think about this together. The horizontal distance the ball travels is 45 meters, and we know the initial horizontal velocity is 15 m/s. Using the formula for horizontal distance, time, and velocity, we can calculate the time it takes for the ball to reach the ground. Then, we can use this time in the vertical motion formula to find the height of the cliff. Remember, mistakes are just happy accidents in the world of math!
How far from the base of the cliff do the keys land?
To determine how far from the base of the cliff the keys land, we need to know the height of the cliff and the initial conditions of the keys’ fall, such as any horizontal motion if applicable. Assuming the keys are dropped straight down with no initial horizontal velocity, they will land directly at the base of the cliff. However, if there is an initial horizontal velocity, we would need to calculate the time of fall and the horizontal distance covered during that time to find the exact landing point.
Can a rock falling from a cliff have a constant acceleration?
Yes, a rock falling from a cliff will experience a constant acceleration due to gravity, which is approximately 9.8 m/s². Ignoring air resistance, the rock will continue to accelerate at this rate until it reaches the ground.
A ball is thrown horizontally from a cliff at a speed of 9 meters per second What is its speed one second later?
Ignoring air resistance, its horizontal speed is still 9 meters per second, its vertical speed is approx. 9.81 m/s, as the acceleration of gravity is 9.81 meters per second per second.
Does a rock falling from a cliff have a constant acceleration?
Yes. Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration. Mass does not affect the acceleration of the body. According to Newton's second law: F=m*a m*g=m*a g=a F= Force m= mass a= acceleration g= gravity acceleration m*g= the force of gravity
Why shouldn't you build on the edge of a cliff?
because the cliff is constantly being eroded by the elements. they will cause the cliff to be undercut and eventually the cliff will collapse.
If you rolled two rocks of a cliff which one would hit the ground first?
it depends wich two kind of rocks are u rolling???
A ball is thrown horizontally at 20 ms from the top of a cliff 50 meters high. How far from the base of the cliff does the ball strike the ground?
the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
A ball is thrown horizontally at 20 from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
Did anyone get on the little island by Mercay Island?
I got there. Where the tree is that you rolled into to get the big green rupee, just to the left bomb it the cliff will crack and there will be a bridge!
When did piggy die?
Piggy died when the boys rolled the rock. He fell off the cliff and the rock smashed him into pieces. Poor piggy. Pork, anyone?
A person on a very high cliff throws a ball vertically up at an initial speed of 13.0 ms Neglect friction whats the speed at the highest point the acceleration at the highest point?
At the highest point, the speed of the ball is 0 m/s because it momentarily stops before falling back down. The acceleration at the highest point is equal to the acceleration due to gravity (approximately -9.8 m/s^2) acting in the downward direction.
