0
What else can I help you with?
What is the differential pressure calculation formula used to determine the pressure difference between two points in a system?
The formula to calculate differential pressure is P P2 - P1, where P is the pressure difference, P2 is the pressure at the second point, and P1 is the pressure at the first point.
If a gas has a pressure of 50.0 mm Hg at 540 K what will be the pressure at 200K if the volume does not change?
If you dcrease the temperature you will decrease the pressure proportionately. So, T1 over T2 will equal P1 over P2. We can derive the formula P1 x T2 = P2 x T1. Substitue the values and we get 50.0 mm x 200K = P2 x 540K 10,000 mmK = P2 x 540K 10,000mmK / 540K = P2 P2 = 18.52 mm of Mercury in a constant volume
A tire has a pressure of 325 kPa at ten degrees Celsius. If the temperature rises fifty degrees Celsius and the volume remains constant what is the new pressure?
Use the ideal gas law: P1/T1 = P2/T2. Rearrange the equation to solve for P2: P2 = (P1/T1) * T2. Plug in the values: P2 = (325 kPa / 283 K) * 60 degrees Celsius. Convert the temperature to Kelvin: 60 degrees Celsius + 273 = 333 K. Calculate the new pressure: P2 ≈ 361 kPa.
What is p2 in boyles law?
In Boyle's Law, p2 represents the final pressure when a gas undergoes a change in volume at constant temperature. The law states that the initial pressure (p1) times the initial volume (V1) is equal to the final pressure (p2) times the final volume (V2), where p1V1 = p2V2.
32 psi at 32 degrees Fahrenheit is how many psi at 110 degrees Fahrenheit?
To find the new pressure at 110 degrees Fahrenheit, you can use the ideal gas law equation: P1/T1 = P2/T2. Given P1=32 psi, T1=32°F, and T2=110°F, you can solve for P2. Substituting the values, you find: 32 psi / 32 + 460 = P2 / 110 + 460. Now converting the temperatures to Rankine, you can solve for P2.
How do you find the equation of a line when given two different points?
You use the well-known point-point formula . Here is it: suppose P1 = (x1,y1) and P2 = (x2,y2) An equation for the line containing P1 and P2 is y - y1 = [(y1-y2)/(x1-x2)] (x -x1) Note that the quantity in brackets is the slope of the line. Note also that it does not matter which point is P1 and which is P2.
What is chain of pointers?
A pointer can point to address of another pointer. consider the exampleint x=456, *p1, **p2;p1 = &x;p2 = &p1;Copyright Einstein College of EngineeringDepartment of Civil EngineeringTOPprintf("%d", *p1); will display value of x 456.printf("%d", *p2); will also display value of x 456. This is because p2 point p1, and p1 points x.Therefore p2 reads the value of x through pointer p1. Since one pointer is points towards anotherpointer it is called chain pointer. Chain pointer must be declared with ** as in **p2
What is the midpoint formula for the elasticity of demand?
Price elasticity demand formula end point formula epd= [q2-q1/q1]/[p2-p1/p1] midpoint formula epd= [q2-q1/(q2+q1)/2] / [p2-p1/(p2+p1)/2]
What is the differential pressure calculation formula used to determine the pressure difference between two points in a system?
The formula to calculate differential pressure is P P2 - P1, where P is the pressure difference, P2 is the pressure at the second point, and P1 is the pressure at the first point.
How do you caluculate the GCD of two prime numbers?
Let p1 and p2 be the two prime numbers. Because they are prime, their divisors are div(p1) = {1,p1} and div(p2) = {1,p2}. So GCD(p1,p2) = Greatest Common Divisor of p1 and p2 = p1 if p1 equals p2 1 if p1 is different from p2
What is the bond order of P2?
The bond order of P2 is 2.
Can a multiple of a prime number be prime?
No. Let p1 be a prime number. Let p2 be a multiple of p1 such that p2 = p1 * k. Then the factors of p2 are: 1, p1, k and p2. ==> p2 is not a prime number. Hence, a multiple of a prime number cannot be a prime number.
How much does a P2 cost?
A P2 costs $9.00 per user/month.
How do you Factorise p2 plus 10d plus 7?
p2+10d+7
What is the answer when you factorise p2 plus 3p?
p2 + 3p = p (p + 3)
How to Reverse a string using pointers in C?
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char str1[]="ravi kant yadav"; char str2[20],*p1,*p2; clrscr(); p1=str1+strlen(str1)-1; //Make p1 point to end of str1. p2=str2; while(p1>=str1) *p2++=*p1--; *p2='\0'; printf("Original string=%s. Reversed String=%s",str1,str2); getch(); }
Factor the expression p2 - 25?
p2 - 25 = (p - 5)(p + 5)
