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What is the minimum force required to pull a 50 kg bag of fertilizer across the floor if the coefficient of friction is 0.37?
Wiki User
∙ 13y ago
The formula for friction is
Fr = μR
Where μ is the coefficient of friction, and
R is the normal contact force.
So the normal contact force will be
Mass x gravity = 50*9.81 = 490.5
0.37 * 490.5 = 181.485 N
It is worth noting that that answer is too precise and also that I ignored the vectors and just used magnitude, in more difficult problems you will need to use vectors.
Wiki User
∙ 13y ago
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