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Acceleration is the change in velocity over a time period. Since you need to know the change in velocity to calculate acceleration, the question being asked is not answerable.
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Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
What is the distance a freely falling object will fall in each second?
Objects in free fall will be accelerating, so you need to know which second that you are interested in, and the acceleration from gravity (9.8 meters per sec2) The formula for distance is: d = v0*t + (1/2)*a*t2. Where v0 is the initial velocity, t is time, and a is acceleration.
How is 1 newton defined?
By Newton's Second Law (the way it is usually presented), as the product of mass x acceleration. That is, the newton is the force required to provide an object with a mass of 1 kg an acceleration of 1 meter/second squared.
What are the factors that cause acceleration?
Acceleration of an object is caused by the application of a force to it. Heavier objects take more force to accelerate them. Acceleration is measured by how many metres per second of speed is added every second, so it's in metres/second/second or metres per second2. The force is related to the mass and acceleration by Newton's second law: Force = mass x acceleration. In this equation metric units can be used, with the force measured in Newtons, the mass in kilograms and the acceleration in metres/second2. A 1-kg mass falling under gravity accelerates at 9.806 metres/second2 . This means that the gravity force, or weight, on a 1-kg mass is 9.806 Newtons. Metric units don't have to be used, any other set of dynamical units can be used, for example mass can be in pounds, the force in poundals and the acceleration in ft/sec2. The weight of a 1-pound mass is 32.2 poundals. If force is measured in pounds instead, the dynamical unit for mass is then the slug, and a 1-slug mass is a mass of 32.2 pounds.
What is expressed in meters per second per second?
It is acceleration that is measured in distance per unit of time per unit time, or in meters per second per second, as the question asked. The only thing missing is the direction vector.
How many newtons is required to make a 7500 kg object go from 0 mph to 60 mph in 1 second?
Convert the speed to meters per second. If you divide this by 1 second, you get the acceleration - since the time is 1 second, the speed and acceleration will be numerically equal. Then use Newton's Second Law: force = mass x acceleration, to find the force.
A train travels at 30 meters per second and stops in 1 minute what its acceleration?
Average acceleration over an interval of time = (final speed - initial speed) / (time for the change)= [ (0 - 30) / 1 ] (meters / second-minute) = [ (0 - 30) / (60) ] (meters / second-second) =-0.5 meter / sec2
If a rock is dropped and it's speed increases from 0 to 4.9 in about 3 seconds. what is the acceleration?
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
What is the relationship of force to mass and mass to force to law of acceleration?
It is best expressed by Newton's second law: Force = Mass x acceleration. Thus a force of 1 Newton produces an acceleration of 1 m/sec per second on a mass of 1 kg. A force of 1 poundal produces an acceleration of 1 ft/sec per second on a mass of 1 pound.
How much is the acceleration of a baseball thrown if the ball goes from 0 to 90 mph in a one-second time period?
Acceleration is change of speed / time, so in this case you have 90 miles per hour per second. While this is a valid unit of acceleration (a unit of distance divided by two time units), you may want to convert this to other units. Reminder: 1 hour = 3600 second; and 1 mile = 5280 feet.
One centimeter per second per second?
That's the magnitude of an acceleration. It's roughly 1/980th the acceleration of gravityat the earth's surface.
What is the distance a freely falling object will fall in each second?
Objects in free fall will be accelerating, so you need to know which second that you are interested in, and the acceleration from gravity (9.8 meters per sec2) The formula for distance is: d = v0*t + (1/2)*a*t2. Where v0 is the initial velocity, t is time, and a is acceleration.
What is the average acceleration of a car goes form 0 to 60 mph in 2.1 seconds?
Average acceleration = (change in speed) / (time for the change) = (60 - 0) / (2.1) = 28.571 miles per hour per second, or 41.905 feet per second2 Using: (1 mile / hour - second) x (5,280- ft / mile) / (3,600 second / hour) = 1.4666 ft/sec2
What does the phrase 1 meter per second mean?
It's a measure of acceleration. It means something is gaining 1 m/s of speed every second it accelerates.
A rocket gose from 0 m per second to 560 m per second in the first 7 seconds of flight What is your acceleration?
a = m/s/s a = 560/1/7 a = 80m/s/s
What is the acceleration of an object that travels 8 meters in 1 second 8 meters in the 2nd second and 8 meters in the 3rd second?
Acceleration is the increase in speed from one unit of time to the next, so the described object has no acceleration. Its speed is constant.
