To calculate the time of the cycle you just invert the Hz value.
Hz = 1 / T, Where T is the time of the cycle in seconds so a 10,000Hz signal has a time of each cycle of: 0.0001 seconds.
The period of a waveform is the reciprocal of its frequency. For a clock waveform with a frequency of 500 kHz, the period can be calculated as 1 / 500 kHz = 2 microseconds.
Period = reciprocal of frequency = 1 / (500) = 0.002 second
The pulse repetition period is the inverse of the pulse repetition frequency. Therefore, if the pulse repetition frequency is 1 kHz, the pulse repetition period would be 1 millisecond (1/1000 seconds).
SONAR uses frequencies typically ranging from 10 kHz to 100 kHz for underwater communication and detection. The frequency used depends on factors such as the depth of the water being surveyed and the desired resolution of the SONAR system. Lower frequencies like 10 kHz are used for deep water surveying, while higher frequencies like 100 kHz offer better resolution for shallower depths.
kHz means 1000 hertz. To convert from kHz to hz, multiply the number of kHz by 1000 and the product will be in hertz.
BW = (1 MHz - 10 KHz) = (1,000 KHz - 10 KHz) = 990 KHz
The period of a waveform is the reciprocal of its frequency. For a clock waveform with a frequency of 500 kHz, the period can be calculated as 1 / 500 kHz = 2 microseconds.
Frequency = 1/period1/7.5 x 10-3 = 1331/3 Hz = 2/15 KHz
Period = (1/frequency) = 1/104 = 10-4 = 0.0001 second = 0.1 millisec = 100 micro sec.
Period = reciprocal of frequency = 1 / (500) = 0.002 second
AM radios can use frequencies in the range 535 kHz to 1605 kHz. Frequencies are assigned at 10 kHz intervals, from 540 kHz to 1600 kHz.
.001 seconds.
(Left + Right) program . . . . 15 Hz - 15 KHz. Stereo pilot . . . . . 19 KHz (Left - Right) program . . . . . 23 - 53 KHz Available subcarriers . . . . . FM, ± 10 KHz pk deviation, 10% injection, cxr 58 KHz and 67 KHz
0.95 kHz = 950 Hz So period = 1/950 seconds = 0.001053 seconds (approx)
If 10 V input causes a frequency shift of 4 kHZ then 2,5v causes a freuency shift of 1 kHz. The input signal frequency of 1 kHz is irelevant.
Since period is the reciprocal of frequency, i.e Period = 1/frequency: Frequency = 4 kHz = 4000 cycles/sec Period = 1/(4000 cycles/sec) = 1 sec/4000 cycles = 0.00025 sec/cycle
The pulse repetition period is the inverse of the pulse repetition frequency. Therefore, if the pulse repetition frequency is 1 kHz, the pulse repetition period would be 1 millisecond (1/1000 seconds).