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Synonyms. Same thing! It all comes down to electron interactions and configurations for both.
Lets take a simple example. Sodium Bicarbonate reacts with dilute sulphuric acid.

2NaHCO3 + H2SO4 -> Na2SO4 + 2CO2 + 2H2O.

So we see that the HCO3- is replaced by SO42- group. How? Well that is due to bond breaking. The ionic bond existing between the Na atom and the bicarbonate radical is broken by the sulphate group of sulphuric acid. So we see that bond breaking is responsible for the above reaction. Lets take a more complex reaction .

An Alkyl halide R-X reacting with Na metal. The reaction is:-

R-X +2Na+ X-R -> R-R + 2NaX

How? By bond breaking. Here the covalent bond is broken by the Na metal which gives rise to 2 alkyl cation and 2 halide anion. The halide anion is bonded ionically with the Na atom and the 2 Rs are bonded together using sigma bonds(or simply covalent bonds). Thus a chemical reaction is governed by bond breaking.

Note: The above mentioned reaction is carried out in the presence of pure and dry ether.

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