What is the velocity of an 500 kg elevator that has 4000 J of energy?

Answer 1

4m/s

Answer 2

To find the velocity of the elevator, we can use the principle of conservation of energy. The kinetic energy of the elevator is equal to the potential energy it possessed. Therefore, we can equate the kinetic energy to the potential energy, and solve for the velocity using the formula: (KE = \frac{1}{2}mv^2), where (KE) is the kinetic energy, (m) is the mass of the elevator, and (v) is the velocity. Substituting the given values, we get (4000 J = \frac{1}{2} \times 500 , \text{kg} \times v^2). Solving for (v), we find the velocity to be approximately (8 , \text{m/s}).

Answer 3

4 m/s. 1/2(500kg) • v^2 = 4,000J

V = √(4000÷250) = 4 m/s

Answer 4

Velocity=4