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Well, darling, at standard conditions, 40 grams of argon gas would occupy approximately 22.4 liters. That's assuming you're talking about STP, where the pressure is 1 atmosphere and the temperature is 0 degrees Celsius. So, there you have it, 40 grams of argon gas takes up about as much space as a medium-sized beach ball.
What else can I help you with?
What is the density of argon gas?
The density of argon gas at standard conditions (0°C and 1 atm pressure) is approximately 1.784 g/L.
What is the volume occupied by 10.7g of argon gas at apressure of 1.1 ATM and a temperrature of 448K?
Using the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is number of moles, R is the ideal gas constant, and T is temperature, we can calculate the volume of gas. First, calculate the number of moles of argon using the given mass and molar mass of argon. Then, plug in the values into the equation to solve for volume. The volume of 10.7g of argon gas at 1.1 ATM and 448K is approximately 2.7 L.
What is the volume occupied by 26.9g of argon gas at a pressure of 1.23 and a temperature of 374?
To calculate the volume of the gas, you would need the ideal gas law equation: PV = nRT. First, convert grams of argon to moles using the molar mass of argon. Then, plug the values of pressure (P), temperature (T), and gas constant (R) into the equation with the calculated number of moles (n) to solve for volume (V).
What is the volume of 1270.0 g argon if the density of argon is 1.784 times 10 1 dm3?
To find the volume, divide the mass of argon by its density. Volume = Mass / Density = 1270.0 g / (1.784 x 10^1 g/dm^3) = 71.097 dm^3
What the density of argon?
1.784 g/cm31.8 gL-1
How many argon atoms in one cc volume?
In one cubic centimeter (cc) of a gas at standard conditions (0°C and 1 atm), there are approximately 2.46 x 10^19 argon atoms. This calculation is based on Avogadro's number and the molar volume of gases under standard conditions.
How many moles of argon gas Ar are present in 5.6 liters of argon gas at standard conditions?
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
How many percent by volume does argon have?
Argon makes up about 0.93% of the Earth's atmosphere by volume.
What is the volume by percent of argon?
The volume percentage of argon in a gaseous mixture can be calculated using the ideal gas law equation, where the volume percentage of argon would be the volume of argon divided by the total volume of the mixture times 100.
What is the density of argon gas?
The density of argon gas at standard conditions (0°C and 1 atm pressure) is approximately 1.784 g/L.
What ion is argon is mostly likely to form in compounds?
Argon does not form compounds in standard conditions.
What is the volume occupied by 10.7g of argon gas at apressure of 1.1 ATM and a temperrature of 448K?
Using the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is number of moles, R is the ideal gas constant, and T is temperature, we can calculate the volume of gas. First, calculate the number of moles of argon using the given mass and molar mass of argon. Then, plug in the values into the equation to solve for volume. The volume of 10.7g of argon gas at 1.1 ATM and 448K is approximately 2.7 L.
What is the volume occupied by 2.20 mol of argon at STP?
The volume occupied by 2.20 mol of argon at standard temperature and pressure (STP) is approximately 49.68 liters. This is calculated using the ideal gas law equation, V = nRT/P, where n is the number of moles, R is the gas constant, T is the temperature, and P is the pressure. At STP, T = 273 K and P = 1 atm.
What is argon percent by volume?
Argon typically makes up about 0.93% of Earth's atmosphere by volume.
What is the volume occupied by 26.9g of argon gas at a pressure of 1.23 and a temperature of 374?
To calculate the volume of the gas, you would need the ideal gas law equation: PV = nRT. First, convert grams of argon to moles using the molar mass of argon. Then, plug the values of pressure (P), temperature (T), and gas constant (R) into the equation with the calculated number of moles (n) to solve for volume (V).
How many mole of argon gas will fill a volume of 116.7 L?
To determine the number of moles of argon gas required to fill a volume of 116.7 L, we first need to convert the volume to liters. Using the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature, we can calculate the number of moles. Given that argon gas is at STP (standard temperature and pressure), we can use the standard values of 1 atm for pressure and 273 K for temperature.
What is the argon percentage in Earth's atmosphere?
The percentage of Argon in the atmosphere is 0.93% in volume.(0.934 to be more accurate-pip)The atmosphere is 0.934% argon by volume, so, a lot of argon.The earth's atmosphere has a volume of about 3x1024 m3, which means that there are about 2.8x1022 m3 (5x1012 mi3) of argon in the atmosphere. The density of argon is about 1.77 kg/m3 so there are about 1.58 kg of argon in the atmosphere.
