You can use the formula pV = nRT, and since it's Standard Temperature and Pressure, p = 1 bar, T = 273 K.
V = nRT/p = 2.2*0.08314*273/1 = 49.9 liters
Argon is a gas at STP. It becomes a liquid below -186oC and solid below -190oC at StP
To calculate the moles of argon present at standard temperature and pressure (STP), you can use the ideal gas law equation PV = nRT. At STP, the pressure is 1 atm and the temperature is 273 K. If you know the volume of the argon gas, you can rearrange the equation to solve for moles, n.
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
At standard temperature and pressure (STP), the volume occupied by 1 mole of any ideal gas is 22.4 liters. Therefore, the volume of 1.42 moles of ammonia at STP would be 1.42 * 22.4 liters = 31.808 liters.
The volume occupied by 0.25 mol of any ideal gas at standard temperature and pressure (STP) is approximately 5.6 L. This is based on the molar volume of an ideal gas at STP, which is around 22.4 L/mol.
To find the volume occupied by 1.5 x 10²³ atoms of argon gas at standard temperature and pressure (STP), we first need to calculate the number of moles. Using Avogadro's number (6.022 x 10²³ atoms/mole), we find that 1.5 x 10²³ atoms corresponds to approximately 0.25 moles of argon. At STP, one mole of an ideal gas occupies about 22.4 liters, so 0.25 moles of argon would occupy about 5.6 liters.
Argon is a gas at STP. It becomes a liquid below -186oC and solid below -190oC at StP
To calculate the moles of argon present at standard temperature and pressure (STP), you can use the ideal gas law equation PV = nRT. At STP, the pressure is 1 atm and the temperature is 273 K. If you know the volume of the argon gas, you can rearrange the equation to solve for moles, n.
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
At standard temperature and pressure (STP), the volume occupied by 1 mole of any ideal gas is 22.4 liters. Therefore, the volume of 1.42 moles of ammonia at STP would be 1.42 * 22.4 liters = 31.808 liters.
The volume occupied by 0.25 mol of any ideal gas at standard temperature and pressure (STP) is approximately 5.6 L. This is based on the molar volume of an ideal gas at STP, which is around 22.4 L/mol.
To find the volume occupied by 20.4 liters of CO2 at STP (Standard Temperature and Pressure, defined as 0°C and 1 atm), we can use the ideal gas law and the concept of proportionality. At STP, 1 mole of gas occupies 22.4 liters, and 1200 torr is approximately 1.58 atm. Using the combined gas law, we can calculate the volume at STP: [ V_{STP} = V_{initial} \times \frac{P_{initial}}{P_{STP}} \times \frac{T_{STP}}{T_{initial}} ] Substituting the known values, the volume at STP will be approximately 12.9 liters.
Argon is a gas at STP.
The molar volume of any ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Converting 39.6 dm3 to liters gives 39.6 L. To find the mass of argon gas, we calculate the number of moles using the ideal gas equation (PV = nRT) and then multiply by the molar mass of argon.
At STP, 1 mole of any gas occupies 22.4 L. Therefore, in a 5L sample of argon at STP, there would be 5/22.4 moles of argon, which is approximately 0.223 moles.
The amount of oxygen is 0,067 moles.