Let us use the expression E = h v
v is the frequency in Hz
So v = E / h
E = 1.4 x 10-21 J
h = planck's constant = 6.676 x 10-34 Js
Plug and solve for v
So v = 2112.9 G Hz
To have wavelength lambda we have to use the expression lambda = c/v
c = the velocity of light in vacuum ie 3 x 108 m/s
Plug and solving we get lambda = 1.42 x 10-4 m
For electromagnetic radiation,c = speed of light = 3.0 x 108 m/s = frequency x wavelengthAs the frequency of light waves increase, the wavelength decreases. For electromagnetic radiation, the wavelength times the frequency equals the speed of light, c, which is 3.0 x 108 m/s. So, if the frequency increases, the wavelength will decrease, and if the wavelength increases, the frequency decreases.
No, the energy of a photon is directly related to its frequency, not its period. Photons with the highest energy have the shortest wavelength and the highest frequency. Period is the time taken to complete one full cycle of a wave, and it is inversely related to frequency.
Remember that for any wave, wavelength x frequency = speed (of the wave). So, as the wavelength increases, the frequency decreases. Also, since the energy of a photon is proportional to the frequency, the energy will decrease as well in this case.
The energy of a photon is determined by its frequency or wavelength, following the equation E = hf, where E is energy, h is Planck's constant, and f is frequency. Photons with higher frequencies have more energy.
The energy of a photon depends on it's frequency
Energy of light photons is related to frequency as Energy = h(Planck's constant)* frequency Frequency = velocity of wave / wavelength So energy = h * velocity of the wave / wavelength
-- longest wavelength -- lowest frequency
Wavelength, energy, color (if visible).
the lowest frequency Lester was here
For electromagnetic radiation,c = speed of light = 3.0 x 108 m/s = frequency x wavelengthAs the frequency of light waves increase, the wavelength decreases. For electromagnetic radiation, the wavelength times the frequency equals the speed of light, c, which is 3.0 x 108 m/s. So, if the frequency increases, the wavelength will decrease, and if the wavelength increases, the frequency decreases.
No, the energy of a photon is directly related to its frequency, not its period. Photons with the highest energy have the shortest wavelength and the highest frequency. Period is the time taken to complete one full cycle of a wave, and it is inversely related to frequency.
A high energy light will have a shorter wavelength than a low energy light. If the wavelength goes down, then the frequency goes up. When calculating energy in the equation, E=hv, frequency (v) is the variable, not the wavelength. So in the equation, if you wanted a more energy (E), you would have the frequency be large. For the frequency to be big, then the wavelength has to be low.
Remember that for any wave, wavelength x frequency = speed (of the wave). So, as the wavelength increases, the frequency decreases. Also, since the energy of a photon is proportional to the frequency, the energy will decrease as well in this case.
They are inversely proportional or relationship to each other.
The energy of a photon is determined by its frequency or wavelength, following the equation E = hf, where E is energy, h is Planck's constant, and f is frequency. Photons with higher frequencies have more energy.
The energy of a photon depends on it's frequency
No, the speed of light in a vacuum is constant for all photons regardless of their energy. Higher energy photons have a higher frequency and shorter wavelength, but they still travel at the speed of light.