Theoretically (I use that loosely) and most commonly identified as the electrical potential. Look in a physics book next time, but the formula for is U = kQq/r. I'm not giving you what the variables stand for because I am a dick. Also because you need to try to learn something but RESEARCH, not stupid questions.
KTHX BAI.
The potential of a charge placed at infinity is zero. This is because the potential at a point due to a charge is the work done in bringing the unit positive charge from infinity to that point, and since no work is done to bring a charge from infinity to itself, the potential at infinity is zero.
The work done in bringing a unit positive charge from infinity to a certain point while keeping it in equilibrium is called the electric potential at that point. It is a measure of the potential energy that a unit positive charge would have at that location.
The measure of the potential energy of an electric charge is called electric potential. It is defined as the work done per unit charge in bringing a test charge from infinity to a specific point in an electric field. The unit of electric potential is the volt.
The work done by the electric field on a point charge is equal to the product of the charge and the change in electric potential energy.
Yes, that's what it means. No force would be required to keep a test point-charge moving along a line of zero potential in the direction toward that point, and there would be no force attracting it toward that point in the combined field. Of course that's physically impossible in the real world, probably because there's no such thing as a point charge. The smallest possible test-charge would still have some non-zero physical dimensions, and be made of atoms whose charge distribution inside it is non-uniform. So it could never stay exactly on the line, and any slight perturbation would require force to execute a mid-course correction and put it back on the zero-potential. Even if there is no continuous contour of zero potential available for the trip, if the test charge starts out and arrives at points of zero potential, then the work done along the way to push it against an occasional repelling force is exactly equal to the work done by an occasional attracting force, and they add up to zero for the trip.
The potential of a charge placed at infinity is zero. This is because the potential at a point due to a charge is the work done in bringing the unit positive charge from infinity to that point, and since no work is done to bring a charge from infinity to itself, the potential at infinity is zero.
The work done in bringing a unit positive charge from infinity to a certain point while keeping it in equilibrium is called the electric potential at that point. It is a measure of the potential energy that a unit positive charge would have at that location.
The work to be done to bring a unit positive charge from infinity to a point in an electric field exists which is having a magnitude unity and direction opposite to the movement of the unit charge.
it is defind as the amount of work done to bring a unit positive charge from infinity to that point in the electric feild it is devoted by V .: electric potential = workdone/charge V=w/q si unit is v
The measure of the potential energy of an electric charge is called electric potential. It is defined as the work done per unit charge in bringing a test charge from infinity to a specific point in an electric field. The unit of electric potential is the volt.
No, work done in moving a charge from infinity to a given point does not involve any acceleration. Work is defined as the product of force and displacement, and in the case of moving a charge, the force is constant along the path. Since acceleration is the rate of change of velocity, and there is no change in velocity in this case, there is no acceleration involved.
The work done by the electric field on a point charge is equal to the product of the charge and the change in electric potential energy.
Yes, that's what it means. No force would be required to keep a test point-charge moving along a line of zero potential in the direction toward that point, and there would be no force attracting it toward that point in the combined field. Of course that's physically impossible in the real world, probably because there's no such thing as a point charge. The smallest possible test-charge would still have some non-zero physical dimensions, and be made of atoms whose charge distribution inside it is non-uniform. So it could never stay exactly on the line, and any slight perturbation would require force to execute a mid-course correction and put it back on the zero-potential. Even if there is no continuous contour of zero potential available for the trip, if the test charge starts out and arrives at points of zero potential, then the work done along the way to push it against an occasional repelling force is exactly equal to the work done by an occasional attracting force, and they add up to zero for the trip.
Everything. A positive charged particle generates an electric field equivalent to the work done in bringing a unit positive charge from infinity to near that charge.
The work done in moving a charge between two points is given by the formula: Work = Charge x Voltage Given the charge z coulombs and voltage difference of 128V - 118V = 10V, the work done would be z coulombs x 10V = 10z joules.
No one because infinity is not a number.
The electrostatic potential is a scalar quantity that represents the potential energy of a unit positive charge at a specific point in the electric field. It is defined as the work done in moving a unit positive charge from infinity to that point. This potential does not depend on the path taken and can be defined at any point in a region of space regardless of the presence of an electric field.