The work done on the brick is 700 J. Work is calculated as force multiplied by distance, so 70 N * 10 m = 700 J.
Yes, work is done when you lift a brick against gravity because you are exerting a force over a distance in the direction of the force of gravity. Work is defined as force multiplied by distance in the direction of the force, so lifting the brick requires work to be done.
The work done on the chair can be calculated using the formula: work = force x distance x cos(theta). Given a net force of 30 N and a distance of 89 m, the work done on the chair is 30 N x 89 m x cos(0°) = 2670 Joules.
The work done by the man is 1500 Joules. This is calculated by multiplying the force (150 N) by the distance the box was pushed (10 m). Work is the product of force and distance, in this case, the man exerted a force of 150 N to move the box 10 m across the room.
The force on the rubber brick is less than the house brick because the rubber brick is less dense and lighter, requiring less force to lift it. The house brick is denser and heavier, leading to a greater force needed to lift it, as indicated by the force meter.
The force diagram for a crate being pushed across the floor would typically show a horizontal force in the direction of the push, a normal force (perpendicular to the surface), and a frictional force opposing the motion. The sum of these forces determines the crate's acceleration or equilibrium.
Yes, work is done when you lift a brick against gravity because you are exerting a force over a distance in the direction of the force of gravity. Work is defined as force multiplied by distance in the direction of the force, so lifting the brick requires work to be done.
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The work done on the chair is calculated by multiplying the force applied (30 N) by the distance moved (9 m) and the cosine of the angle between the force and the direction of movement. Since the force is horizontal and the chair is moved horizontally, the angle is 0 degrees. Therefore, the work done is (30 N) * (9 m) * cos(0) = 270 Nm = 270 J.
First you need to calculate the work required. This is simply force x distance in this case.Once you have that, divide the work by the time.
The work done on the chair can be calculated using the formula: work = force x distance x cos(theta). Given a net force of 30 N and a distance of 89 m, the work done on the chair is 30 N x 89 m x cos(0°) = 2670 Joules.
The work done by the man is 1500 Joules. This is calculated by multiplying the force (150 N) by the distance the box was pushed (10 m). Work is the product of force and distance, in this case, the man exerted a force of 150 N to move the box 10 m across the room.
The force on the rubber brick is less than the house brick because the rubber brick is less dense and lighter, requiring less force to lift it. The house brick is denser and heavier, leading to a greater force needed to lift it, as indicated by the force meter.
The force diagram for a crate being pushed across the floor would typically show a horizontal force in the direction of the push, a normal force (perpendicular to the surface), and a frictional force opposing the motion. The sum of these forces determines the crate's acceleration or equilibrium.
The mechanical work done in holding a brick 1 meter above the floor is zero, as work is defined as the force applied over a distance. While you exert an upward force equal to the weight of the brick to keep it suspended, there is no displacement in the direction of the force since you are not moving the brick. Thus, even though you are applying force, the lack of movement means no mechanical work is done.
The work done on the cart would be 200 Joules. This is calculated using the formula Work = Force x Distance, where Work = 50 N x 4 m = 200 J.
The work done on the ship can be calculated by multiplying the force applied by the distance over which it is applied, giving a result in joules (J). The formula for work is W = force x distance x cos(theta), where theta is the angle between the force and the direction of motion. If the force is horizontal and the ship moves horizontally, then theta is 0 degrees and cos(0) = 1. Therefore, the work done on the ship is W = force x distance x 1 = N x km.
Workin joules = (89) x (distance she moves the force through)in meters