0
What else can I help you with?
Is work done if you lift a brick?
Yes, work is done when you lift a brick against gravity because you are exerting a force over a distance in the direction of the force of gravity. Work is defined as force multiplied by distance in the direction of the force, so lifting the brick requires work to be done.
What amount of work is done on a chair that is pushed 89 m across a floor by a horizontal 30-N net force?
The work done on the chair can be calculated using the formula: work = force x distance x cos(theta). Given a net force of 30 N and a distance of 89 m, the work done on the chair is 30 N x 89 m x cos(0°) = 2670 Joules.
A man pushing with a force of 150 N pushed a box 10 m across a room. How much work did he do Remember work force and times distance.?
The work done by the man is 1500 Joules. This is calculated by multiplying the force (150 N) by the distance the box was pushed (10 m). Work is the product of force and distance, in this case, the man exerted a force of 150 N to move the box 10 m across the room.
Why is the pull on the force meter for the rubber brick and house brick?
The force on the rubber brick is less than the house brick because the rubber brick is less dense and lighter, requiring less force to lift it. The house brick is denser and heavier, leading to a greater force needed to lift it, as indicated by the force meter.
A force diagram for a crate is pushed across the floor?
The force diagram for a crate being pushed across the floor would typically show a horizontal force in the direction of the push, a normal force (perpendicular to the surface), and a frictional force opposing the motion. The sum of these forces determines the crate's acceleration or equilibrium.
Is work done if you lift a brick?
Yes, work is done when you lift a brick against gravity because you are exerting a force over a distance in the direction of the force of gravity. Work is defined as force multiplied by distance in the direction of the force, so lifting the brick requires work to be done.
A block of mass m=2.50kg is pushed a distance d =2.20m along table by a constant applied force of magnitude F=16.0N directed at an angle =25.0belew the horizontal as shown in Figure . Determine the work done on the block by a- the applied force?
87
What amount of work is don't on a chair pushed 9m across a floor by a horizontal 30-N net force?
The work done on the chair is calculated by multiplying the force applied (30 N) by the distance moved (9 m) and the cosine of the angle between the force and the direction of movement. Since the force is horizontal and the chair is moved horizontally, the angle is 0 degrees. Therefore, the work done is (30 N) * (9 m) * cos(0) = 270 Nm = 270 J.
A student pushed a box 32.0 m across a smooth horizontal floor using a constant force of 124 N. If the force was applied for 8.00 s how much power was developed to the nearest watt?
First you need to calculate the work required. This is simply force x distance in this case.Once you have that, divide the work by the time.
What amount of work is done on a chair that is pushed 89 m across a floor by a horizontal 30-N net force?
The work done on the chair can be calculated using the formula: work = force x distance x cos(theta). Given a net force of 30 N and a distance of 89 m, the work done on the chair is 30 N x 89 m x cos(0°) = 2670 Joules.
A man pushing with a force of 150 N pushed a box 10 m across a room. How much work did he do Remember work force and times distance.?
The work done by the man is 1500 Joules. This is calculated by multiplying the force (150 N) by the distance the box was pushed (10 m). Work is the product of force and distance, in this case, the man exerted a force of 150 N to move the box 10 m across the room.
Why is the pull on the force meter for the rubber brick and house brick?
The force on the rubber brick is less than the house brick because the rubber brick is less dense and lighter, requiring less force to lift it. The house brick is denser and heavier, leading to a greater force needed to lift it, as indicated by the force meter.
A force diagram for a crate is pushed across the floor?
The force diagram for a crate being pushed across the floor would typically show a horizontal force in the direction of the push, a normal force (perpendicular to the surface), and a frictional force opposing the motion. The sum of these forces determines the crate's acceleration or equilibrium.
What amount of work is done on a cart that is pushed 4 meter across a floor by a horizontal 50 Newton net force?
The work done on the cart would be 200 Joules. This is calculated using the formula Work = Force x Distance, where Work = 50 N x 4 m = 200 J.
How much work is done on the ship when if it moves a distance of km with a constant net horizontal force of N?
The work done on the ship can be calculated by multiplying the force applied by the distance over which it is applied, giving a result in joules (J). The formula for work is W = force x distance x cos(theta), where theta is the angle between the force and the direction of motion. If the force is horizontal and the ship moves horizontally, then theta is 0 degrees and cos(0) = 1. Therefore, the work done on the ship is W = force x distance x 1 = N x km.
If she exerts a horizontal force of 89 N on the hay how much work has she done?
Workin joules = (89) x (distance she moves the force through)in meters
Can you increase the horizontal component of the force that you exert on the mower without increasing the magnitude of the force?
No, the horizontal component of a force is directly related to the magnitude of the force. Increasing the horizontal component of the force would require increasing the magnitude of the force itself.
