You are ina jumbo jet moving at 600km/hr you jump streight up where do you land?
The person's push creates a force that accelerates the crate. As long as the force overcomes friction, the crate will move across the floor.
The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.
The force of friction when a crate slides across the floor is dependent on the coefficient of friction between the crate and the floor, as well as the normal force acting on the crate. The frictional force resists the motion of the crate and can be calculated using the equation: frictional force = coefficient of friction * normal force.
The acceleration of the crate will be zero since it is moving at a constant speed. This means that the net force acting on the crate is zero, so the forces pushing it forward are balanced by the forces resisting its motion.
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
The person's push creates a force that accelerates the crate. As long as the force overcomes friction, the crate will move across the floor.
The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.
The force of friction when a crate slides across the floor is dependent on the coefficient of friction between the crate and the floor, as well as the normal force acting on the crate. The frictional force resists the motion of the crate and can be calculated using the equation: frictional force = coefficient of friction * normal force.
The acceleration of the crate will be zero since it is moving at a constant speed. This means that the net force acting on the crate is zero, so the forces pushing it forward are balanced by the forces resisting its motion.
kinetic friction
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
friction
The first time you enter the room. Start by pushing the crate in the southeast corner across to the southwest. Then push the crate in the northwest corner across the room so it toches the iced crate. Stand behind the crate you just pushed and push it to the south. Then push the same crate westone space so it hits the first crate. Now push the crate one more time south and the switch will be activated. The second time you need to enter the room is different. start by pushing the crate to the north south. Go to the south and shove the crate to the middle of the puzzle so it passes over the middle floor switch. Now shove the crate that's on the eastern edge west then north. So Its sitting in front of the middle floor switch. Run to the crate that's furthest north and push it clockwise around the rim of the puzzle so it hits the crete you have yet to move. Finally face north and push the crate so it is on the switch leading upstairs.
80 J
The magnitude of the force of friction on the crate is equal and opposite to the force you apply to push it, as long as the crate is moving at constant speed. This is because the force of friction balances the push force to prevent acceleration.
The magnitude of the force of friction on the crate would be equal to the magnitude of your push. This is because the crate is moving at a constant speed, indicating that the force you are applying is balanced by the force of friction acting in the opposite direction.
The force needed to slide the crate at constant velocity is equal in magnitude but opposite in direction to the force of friction. The force of friction can be calculated as the product of the coefficient of friction and the normal force acting on the crate (weight of the crate). Therefore, the force needed would be 250 kg * 9.8 m/s^2 * 0.25 = 612.5 N.