Short answer: [Ar] 3d10 4s2 4p3
OR
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3
The electron configuration of arsenic is: [Ar]4s23d104p3.
Arsenic has the electron configuration of [Ar] 3d104s24p3
H2 is not an atom, it is a diatomic molecule. Each hydrogen atom has 1 valence electron. When two hydrogen atoms covalently bond to form an H2 molecule, there are two valence electrons being shared by the two atoms.
One valence electron
A halogen is located in group 17 of the periodic table, so the electron configuration for the valance electron would be ns2np5 (n=energy level). So all halogens have 7 valance electrons.
Hydrogen has 1 valence electron. Bromine has 7 valence electrons. When hydrogen and bromine react, the bromine atom 'steals' the hydrogen atom's only electron. The hydrogen atom then has no electrons and the bromine atom has 8 valence electrons. The two atoms are now ions because their number of protons does not equal their number of electrons. The bromine atom is now a bromide anion and the hydrogen atom is now a hydrogen cation (a proton). The two ions remain together, ionicly bonded and together are called hydrogen bromide.
The electron. The electron is has a negative charge. The more electrons that are in a valence shell of the atom the more negative the atom will be.
The valence electrons are the outermost (highest energy) s and p sublevels. There are 5 valence electrons in a phosphorus atom, and it is in period 3, so its valence electron configuration is 3s23p3.
Magnesium (Mg) has atomic number 12, so the electron configuration is1s2 2s2 2p6 3s2. The VALENCE electron configuration would simply be 3s2.
Nitrogen, Phosphorus, Arsenic, Antimony, and Bismuth all have 5 valence electrons
4
The valence electrons are the outermost (highest energy) s and p sublevels. There are 5 valence electrons in a phosphorus atom, and it is in period 3, so its valence electron configuration is 3s23p3.
With an e- configuration of [Ne] 3s23p5, the atom will be found in Group VII A, meaning that there are 7 valence electrons.
calcium has the complete electronic configuration: 2, 8, 8 2 and hence has 2 valence electrons.
It can reveal the number of valence electrons in the last shell.
Just one valence electron. The electron configuration for K-42 is 2-8-8-1, meaning that there is one electron in the outermost "shell" of the atom.
Seven.
Seven.
The electron configuration of beryllium is written as [He] 2s2. This means that it has 2s2 electrons above the configuration of Helium.