1,500 grams2,500 grams500 grams2,000 grams
The extension of a spring depends on its stiffness, which is given by its spring constant. If the spring constant is known, you can use Hooke's Law (F = kx) to calculate the stretch of the spring. For example, if the spring constant is 100 N/m, a 1 kg weight would stretch the spring by 0.1 meters (10 cm).
The length of the spring increases when you add a mass to it due to the force of gravity pulling the mass downwards and stretching the spring. This change in length is proportional to the weight of the added mass and the spring's stiffness.
Hooke's law is not related to any "natural length". Rather, it defines a string constant: how much the string extends or compresses, depending on the applied force. In SI units, the spring constant would be measured in newton/meter.
Using Hooke's Law, we can set up a proportion to solve for the mass of the object stretching the spring 9 cm. Since the force required to stretch a spring is directly proportional to the distance stretched, an object with a mass of 6 kg would stretch it to 9 cm.
The maximum potential energy stored in the spring can be calculated using the formula ( E = \frac{1}{2}kx^2 ), where ( k = 500 N/m ) is the spring constant and ( x = 0.2 m ) is the maximum stretch. Plugging in these values, the stored energy would be ( E = \frac{1}{2} \times 500 \times (0.2)^2 = 10 J ).
The extension of a spring depends on its stiffness, which is given by its spring constant. If the spring constant is known, you can use Hooke's Law (F = kx) to calculate the stretch of the spring. For example, if the spring constant is 100 N/m, a 1 kg weight would stretch the spring by 0.1 meters (10 cm).
It depends on spring energy or spring strength
The length of the spring increases when you add a mass to it due to the force of gravity pulling the mass downwards and stretching the spring. This change in length is proportional to the weight of the added mass and the spring's stiffness.
1979
The ratio of force applied to how much the spring streches (or compresses). In the SI, the spring constant would be expressed in Newtons/meter. A larger spring constant means the spring is "stiffer" - more force is required to stretch it a certain amount.
Without a spring, the lock would never unlock. Therefore, a lock of a door required a spring.
About 1.5 meters in length.
America uses feet; the rest of the world uses meters.
Hooke's law is not related to any "natural length". Rather, it defines a string constant: how much the string extends or compresses, depending on the applied force. In SI units, the spring constant would be measured in newton/meter.
Using Hooke's Law, we can set up a proportion to solve for the mass of the object stretching the spring 9 cm. Since the force required to stretch a spring is directly proportional to the distance stretched, an object with a mass of 6 kg would stretch it to 9 cm.
To determine the mass required to stretch a spring 5.5 cm, you would use Hooke's Law, which states that the force exerted by a spring is proportional to its displacement. The formula is ( F = kx ), where ( F ) is the force (in newtons), ( k ) is the spring constant (in N/m), and ( x ) is the displacement (in meters). You would convert 5.5 cm to meters (0.055 m) and then rearrange the formula to find the mass ( m = \frac{F}{g} ), where ( g ) is the acceleration due to gravity (approximately 9.81 m/s²). Without the spring constant ( k ), the exact mass cannot be calculated.
A spring has maximum potential energy at maximum displacement from equilibrium. This means that the greatest potential energy will occur when a spring is stretched as far as it will stretch or compressed as tightly as it will compress. In an oscillating system, where an object attached to a spring is moving back and forth at a given frequency, the object will oscillate about the equilibrium point, and the potential energy of the system will be greatest (and equal) when the object is farthest from equilibrium on either side.