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What the time periods of a simple pendulum at equator of the earth?
Wiki User
∙ 9y ago
For small swings of a mass suspended on a weightless string, the period is given by T = 2 pi sqrt (a/g) where a is the length of the pendulum and g is the acceleration due to gravity.
Wiki User
∙ 9y ago
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How does the Foucault pendulum work?
The Foucault Pendulum experiment proves that the Earth rotates beneath the pendulum, which proved that the Earth rotates. If one were to make a pendulum on the equator it would not work because it doesnt rotate at that point of the Earth.
How the motion of simple pendulum is affected if it is placed at the center of earth?
If the plumb point of a pendulum is the center of earth, the pendulum will make diametrical oscillations
What is effect on time period of simple pendulum at centre of earth?
At the center of the Earth there would be no effective gravity; a pendulum wouldn't work as a pendulum.
What is the time period of simple pendulum at the center of the earth?
Infinite
What is the time period of simple pendulum at center of earth?
i think it is infinite because acceleration due to gravity at the center of the earth is zero and time period of the simple pendulum is given by 2*3.14*sqrt(l/g)....
How does the Foucault pendulum work?
The Foucault Pendulum experiment proves that the Earth rotates beneath the pendulum, which proved that the Earth rotates. If one were to make a pendulum on the equator it would not work because it doesnt rotate at that point of the Earth.
How the motion of simple pendulum is affected if it is placed at the center of earth?
If the plumb point of a pendulum is the center of earth, the pendulum will make diametrical oscillations
What is effect on time period of simple pendulum at centre of earth?
At the center of the Earth there would be no effective gravity; a pendulum wouldn't work as a pendulum.
Why the motion of simple pendulum is slow at equator?
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
What is the time period of simple pendulum at the center of the earth?
Infinite
What is the time period of simple pendulum at center of earth?
i think it is infinite because acceleration due to gravity at the center of the earth is zero and time period of the simple pendulum is given by 2*3.14*sqrt(l/g)....
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
What part of the earth is the southern hemisphere?
The Southern Hemisphere is the half of Earth that is south of the equator. It includes parts of South America, Africa, Australia, and Antarctica.
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
How earth's rotation affects a pendulum?
A pendulum moves not by Earth's rotation, but by gravity pulling down and causing it to swing.
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
Foucault pendulum is a famous demonstration of Earth's?
A Foucault pendulum is a famous demonstration of Earth's:
