it wont work because glass materials don't pass electricity it wont work because glass materials don't pass electricity by: dalia adel class:6p
The glass of the light bulb is not conductive, so the circuit would not be completed. You would need to join the wires to the positive and negative contacts on the base of the bulb for the circuit to work.
When you move a bulb closer to the battery in a circuit, it will receive more electrical energy as the resistance decreases. This will cause the bulb to shine brighter due to the increased flow of electrical current passing through it.
Adding one more battery to a parallel circuit of two light bulbs would increase the voltage across the entire circuit. This would cause both light bulbs to shine more brightly as they receive more power. It will not affect the current flowing through the circuit but will boost the overall energy provided to the circuit.
When a car battery sparks while connecting it, it could be due to a poor connection or a short circuit. This can happen if the cables are not connected properly or if there is corrosion on the terminals. It is important to ensure that the connections are clean and secure to prevent sparking and potential damage to the battery or the vehicle.
If the bulb is removed from its holder, the circuit will be open, breaking the flow of electricity. This will result in the current being unable to pass through the circuit and the bulb will not light up as a result.
Nothing will happen. There has to be a complete a circuit for the battery to function thus allowing for the flow of electricity.
The glass of the light bulb is not conductive, so the circuit would not be completed. You would need to join the wires to the positive and negative contacts on the base of the bulb for the circuit to work.
It wil be on
Nothing will happen. It requires two wires to complete the circuit. Electrical current travels from the battery terminal through the wire to a metal portion of the base of the lightbulb. The current then travels up through the filament wire which glows as the current travels through. The current then travels back down the other side of the filament wire to the base of the bulb and thus through the second wire back to source, which is the battery.
*Look at the simple circuit illustrated in Figure A-2. What will happen when only switch S1 is closed? Correct Answer= "Nothing will happen-the light bulb won't light up." <<>> If there is a load in the circuit the load will operate. If there is no load in the circuit and it is complete then a short circuit will occur and something in the circuit will burn open. If the circuit is complete and there is a fuse or breaker in the circuit, then the fuse or breaker will open the circuit.
When you start at the negative end of the battery, you start to lose electrons and the circuit is closed.
You would short out the battery. If it was a car battery capable of 300 amps and the wire was big enough, the battery could explode.
the circuit would not be complete. the lightbulb would not light or the buzzer would not buzz
The piece of string will act as an insulator. Insulators will not carry circuit current when a voltage source is applied across it. Therefore nothing will happen if a piece of string is used to complete an electrical circuit.
would discharge in 18 hours
When you move a bulb closer to the battery in a circuit, it will receive more electrical energy as the resistance decreases. This will cause the bulb to shine brighter due to the increased flow of electrical current passing through it.
Believe the answer is a resistor. They are either off (a 0) or on (a 1), and the position determines what circuit is complete and what will happen.