To calculate the stopping distance, we need to know the deceleration of the car, which can be determined using the equation force = mass x acceleration. In this case, the deceleration would be -1 m/s^2. Using the equation stopping distance = (initial velocity)^2 / (2 x acceleration), we find the stopping distance to be 50 meters.
The stopping distance can be calculated using the equation: stopping distance = (initial velocity^2) / (2 * deceleration). The deceleration can be calculated using the formula: deceleration = force / mass. Plugging in the values and calculating will give you the stopping distance.
3000 Kg = 3 tonnes.
No, 300g (grams) is smaller than 3000kg (kilograms) because there are 1000 grams in 1 kilogram.
1 pound = 0.452 kilo so 3000 pounds equals 1356 kilos
change in velocity =accleration. Suppose a car is moving at 30km\hr at 6:30 am and then the velocity of the car is noted to be 100km\hr at 7:30am.thus the change in velocity of the car =100-70=30 km\hr over a time of (6:30am-7:30am) 1hr.Thus the accleration of the car=30km/hr*hr.Force however is the product of the mass of the car and the accleration by which the car is travelling.Let the mass of the car be 100kg.Thus the force =100*30=3000kg*km/hr*hr.
The stopping distance for a 3000kg car if 3000 N of force is applied when the car is traveling 10 ms is 50 meter. This is based on Newton's second law of force.
50m
The stopping distance can be calculated using the equation: stopping distance = (initial velocity^2) / (2 * deceleration). The deceleration can be calculated using the formula: deceleration = force / mass. Plugging in the values and calculating will give you the stopping distance.
3000 Kg = 3 tonnes.
60000
No, 300g (grams) is smaller than 3000kg (kilograms) because there are 1000 grams in 1 kilogram.
3 tonnes
Force = mass X acceleration, F=ma=3000kg X 6m/s2=18000kgm/s2=18 kilonewtons
3000kg. kilograms is a measurement for mass.
3000kg = 6,613lb 13.9oz
3000kg = 6,613lb 13.9oz
round about 3000kg