Then it wouldn't be a very good red filter.
At first blush this appears to be an exceedingly stupid question, but actually while there is in fact such a thing as a stupid question (trust me on this), the advance of science is basically a history of something that "couldn't happen" (according to the currently accepted laws of science) happening, and someone having to come up with a better theory to account for it.
In actual practice, a lot of "red" filters do pass a significant amount of light in the blue region of the spectrum. The amount that gets through is based on the precise hue and saturation of the filter. If it lets through a lot of red and a lot of blue but almost no green, then it's a violet/purpleish red filter. If it lets through a lot of red and a lot of green and blue (but less than the amount of red), it's a pink filter. And so on.
If you put a blue filter in the path of a ray of light, the filter would absorb all colors of light except for blue. This would result in the light passing through the filter appearing blue in color.
If a red light is shined through a blue filter, the blue filter would absorb the red light since it is not in the transmitted light spectrum. This would result in very little to no light passing through the blue filter, creating darkness or a very dim output depending on the intensity of the red light source.
Only the green portion of the white light would pass through the green filter. The filter absorbs all colors except green, allowing only green light to pass through.
It depends on what kind of filter, e.g. a blue filter absorbs everything except blue light, so only blue light comes out, which is why the filter looks blue, and is referred to as a "blue filter".
An emitter of blue light shining on/through a red filter.The red filter appears red because it block all light except red. So trying to shine blue through it should attenuate the blue heavily. Only red can pass through the red filter easily.
If you put a blue filter in the path of a ray of light, the filter would absorb all colors of light except for blue. This would result in the light passing through the filter appearing blue in color.
If a red light is shined through a blue filter, the blue filter would absorb the red light since it is not in the transmitted light spectrum. This would result in very little to no light passing through the blue filter, creating darkness or a very dim output depending on the intensity of the red light source.
A red filter blocks every color except red from getting through, so you would see red.
Only the green portion of the white light would pass through the green filter. The filter absorbs all colors except green, allowing only green light to pass through.
It depends on what kind of filter, e.g. a blue filter absorbs everything except blue light, so only blue light comes out, which is why the filter looks blue, and is referred to as a "blue filter".
An emitter of blue light shining on/through a red filter.The red filter appears red because it block all light except red. So trying to shine blue through it should attenuate the blue heavily. Only red can pass through the red filter easily.
If you place a blue filter in the path of light coming through a red filter, the blue filter will absorb or block the red light, potentially resulting in less intense light or a different color of light that is transmitted through. The combination of the two filters will likely produce a color that is a mix of the two original colors, such as purple or magenta.
When white light passes through a purple filter, the filter will absorb most colors of the white light except for purple, allowing only purple light to pass through. When this filtered purple light then passes through a red filter, the red filter will absorb all colors except for red, thus only allowing red light to pass through. Therefore, you would see red light.
If green light passes through a cyan filter, the filter will absorb some of the green light and allow the rest to pass through. The transmitted light will appear as a slightly dimmed green color due to the absorption of some of the green wavelengths by the filter.
If you put a blue filter in front of a red filter, the blue filter would block all the red light and only allow blue light to pass through. The red filter would then block all the blue light that passed through the blue filter. This would result in no light passing through the filters, so you wouldn't see any color.
If you pass white light through a blue filter, only the blue wavelengths will pass through, resulting in a blue light. If you then pass this blue light through a red filter, none of the blue light will pass through, and you would not see anything as there would be no red wavelengths to transmit.
Red or blue. The reason a red filter looks and is red, is because only red light comes through it, and the same can be said about a blue filter allowing only blue light through. Other colors are absorbed by the dyes in the filter. If white light enters a red filter, then red light comes out, and the same goes for blue.