The force of the rifle on the bullet and the force of the bullet on the rifle are equal in magnitude but opposite in direction, according to Newton's third law of motion. However, the mass of the rifle is much larger than the mass of the bullet, so the acceleration of the rifle is much smaller compared to the acceleration of the bullet.
The acceleration of the bullet is greater than the acceleration of the rifle because the bullet has a much smaller mass. Newton's second law, F=ma, states that the acceleration is inversely proportional to mass given the same force, so the smaller mass of the bullet results in a greater acceleration for the same force applied.
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force (F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
The force of the rifle returning back after firing a bullet is smaller than the force on the bullet because the rifle has a larger mass compared to the bullet. According to Newton's third law, force is equal to mass times acceleration, so the force exerted on the rifle is smaller due to the larger mass and slower acceleration compared to the bullet.
Using Newton's second law (F=ma), the acceleration of the bullet can be calculated by dividing the force by the mass of the bullet. First, convert the mass of the bullet to kg (7.0g = 0.007kg), then divide the force (2.1N) by the mass (0.007kg) to find the acceleration. The acceleration of the bullet would be 300 m/s^2.
Yes, a bullet can potentially knock someone over with the force of impact. However, there are many variables that can influence the effect of a bullet, such as the caliber of the bullet, the distance it is fired from, and where it strikes the body.
The acceleration of the bullet is greater than the acceleration of the rifle because the bullet has a much smaller mass. Newton's second law, F=ma, states that the acceleration is inversely proportional to mass given the same force, so the smaller mass of the bullet results in a greater acceleration for the same force applied.
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force (F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
The force of the rifle returning back after firing a bullet is smaller than the force on the bullet because the rifle has a larger mass compared to the bullet. According to Newton's third law, force is equal to mass times acceleration, so the force exerted on the rifle is smaller due to the larger mass and slower acceleration compared to the bullet.
Using Newton's second law (F=ma), the acceleration of the bullet can be calculated by dividing the force by the mass of the bullet. First, convert the mass of the bullet to kg (7.0g = 0.007kg), then divide the force (2.1N) by the mass (0.007kg) to find the acceleration. The acceleration of the bullet would be 300 m/s^2.
Yes, a bullet can potentially knock someone over with the force of impact. However, there are many variables that can influence the effect of a bullet, such as the caliber of the bullet, the distance it is fired from, and where it strikes the body.
the recoil of a bullet fired from a gun
No, the force of the gun results from the explosion of the gunpowder, propelling the bullet forward. The force of the bullet is the result of the acceleration it receives from the gun's explosion, which propels it in the opposite direction.
The recoil of a bullet being fired from a gun is a good example, the action force is the gun pushing the bullet away from the gun and the reaction force is the bullet pushing back against the gun (recoil).
When a gun is fired, the bullet experiences a greater force than the gun. This is due to Newton's third law of motion, where for every action force there is an equal and opposite reaction force. The force from the expanding gases propels the bullet forward with more force than the recoiling gun experiences.
This equation will tell you how much force is exerted by a bullet, for example, on a target.
The acceleration of the human cannonball can be calculated using Newton's second law, which states that Force = mass * acceleration. In this case, the force is 2400N and the mass is 80kg, so the acceleration is 30 m/s^2.
The force exerted on the bullet can be calculated using the equation for force: force = mass x acceleration. First, calculate the acceleration of the bullet as it comes to a stop using the equation of motion: v^2 = u^2 + 2as, where v is the final velocity (0 m/s), u is the initial velocity (350 m/s), a is the acceleration, and s is the distance travelled (0.12 m). Once you find the acceleration, you can plug it back into the force equation along with the mass of the bullet (2.5 g converted to kg).