because the bullet and the rifle have equal and opposite direction,so a bullet have high kinetic energy and momentum
The force of the rifle on the bullet and the force of the bullet on the rifle are equal in magnitude but opposite in direction, according to Newton's third law of motion. However, the mass of the rifle is much larger than the mass of the bullet, so the acceleration of the rifle is much smaller compared to the acceleration of the bullet.
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force (F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
Yes, when a bullet is fired from a rifle, the bullet typically has greater momentum and kinetic energy compared to the rifle. This is due to the bullet's higher velocity and lower mass compared to the rifle.
The acceleration of the bullet is greater than the acceleration of the rifle because the bullet has a much smaller mass. Newton's second law, F=ma, states that the acceleration is inversely proportional to mass given the same force, so the smaller mass of the bullet results in a greater acceleration for the same force applied.
And opposite momentum. Say bullet muzzle velocity = 15 000 metres per second Say bullet mass = 0.02 kilogram (20 grams) Say rifle mass = 3 kilogram Then > Bullet momentum = 0.02 * 15 000 = 300 kg - m/s Presume Rifle momentum the same , then 300 = 3 * ? ? = 100 metres per second
The force of the rifle on the bullet and the force of the bullet on the rifle are equal in magnitude but opposite in direction, according to Newton's third law of motion. However, the mass of the rifle is much larger than the mass of the bullet, so the acceleration of the rifle is much smaller compared to the acceleration of the bullet.
For every action, there is an equal and opposite reaction. Now the bullet is light (low mass) so when a certain amount of force pushes the bullet forward and the gun backward at the same time, the bullet moves fast. The gun is heavy (great mass) so it is slower to accellerate rearward. It will never reach even a small fraction of the velocity of the bullet. But since force = mass times velocity squared, there is an equal amount of energy in the bullet and the butt stock of the rifle.
A rifle experiences backward kick, or recoil, when a bullet is fired due to Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. When the bullet is propelled forward out of the barrel, the rifle experiences an equal force pushing backward. This recoil results from the rapid expulsion of gas and the mass of the bullet moving forward, leading to the rifle moving backward in response. The amount of recoil is influenced by the bullet's mass and the velocity at which it is fired.
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force (F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
Yes, when a bullet is fired from a rifle, the bullet typically has greater momentum and kinetic energy compared to the rifle. This is due to the bullet's higher velocity and lower mass compared to the rifle.
The acceleration of the bullet is greater than the acceleration of the rifle because the bullet has a much smaller mass. Newton's second law, F=ma, states that the acceleration is inversely proportional to mass given the same force, so the smaller mass of the bullet results in a greater acceleration for the same force applied.
Rifle and bullet (The bullet is dependent on the rifle to accomplish its purpose)
The force exerted on the bullet and the recoil force against the rifleman, are equal to each other (for every action there is an equal and opposite reaction). The bullet has a very small mass, and the rifle/rifleman possess a large mass, force is equal to one half mass times velocity squared, F=m/2*v^2. So velocity of the bullet is the square root of twice force divided by mass, small mass equals large velocity. Another way of looking at this problem is to invoke the law of the conservation of momentum: mass(bullet)*muzzle_velocity(bullet) = mass(rifle)*recoil_velocity(rifle). This is an approximation that neglects the momentum carried away the propellant (both spent and unburned) that exits the muzzle after the bullet.
The barrel guides and accelerates the bullet out of the rifle, and imparts spin to the bullet to stabilize the bullet in flight.
And opposite momentum. Say bullet muzzle velocity = 15 000 metres per second Say bullet mass = 0.02 kilogram (20 grams) Say rifle mass = 3 kilogram Then > Bullet momentum = 0.02 * 15 000 = 300 kg - m/s Presume Rifle momentum the same , then 300 = 3 * ? ? = 100 metres per second
After leaving the rifle, the bullet only has the force of gravity acting on it vertically downwards. In the horizontal direction, there are no horizontal forces acting on the bullet unless there is air resistance or any other external force present.
There is no one answer- it depends on the rifle. They are generally less powerful than a full size battle rifle cartridge. The M16 rifle uses a 5.56mm bullet, the AK47 a 7.62mm bullet, etc.