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When a submerged object is in water, forces such as buoyancy (upward force due to displacement of water), gravity (downward force due to the object's mass), and drag (resistance force due to the object's motion) act on it. These forces determine the object's behavior and whether it sinks, floats, or remains suspended at a certain depth.
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Why are forces exerted on a submerged object due to water pressure not balanced?
Forces are exerted on a submerged object due to water pressure not being balanced due to buoyancy. This is when the pressure at the bottom of the submerged object is greater than the fluid on the top of the object, thus projecting the object upward.
How does the buoyant force of a fully submerged object compare with the weight of the water displaced?
The buoyant force acting on a fully submerged object is equal in magnitude to the weight of the water displaced. This is known as Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the submerged object.
If an object has the same density as the fluid it is submerged in the object will always?
Will always float with the top surface level with the water
How much more does an object weigh after it has been submerged out of water?
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
Why does the object apparently loss weight when completlely submerged in water?
An object will appear to lose weight when completely submerged in water due to the buoyant force acting on it. This force is equal to the weight of the water displaced by the object, causing it to feel lighter in water compared to in air.
Why are forces exerted on a submerged object due to water pressure not balanced?
Forces are exerted on a submerged object due to water pressure not being balanced due to buoyancy. This is when the pressure at the bottom of the submerged object is greater than the fluid on the top of the object, thus projecting the object upward.
What is the relationship between hydrostatic water pressure and the buoyant force acting on a submerged object?
The hydrostatic water pressure increases with depth, which in turn increases the buoyant force acting on a submerged object.
How does the buoyant force of a fully submerged object compare with the weight of the water displaced?
The buoyant force acting on a fully submerged object is equal in magnitude to the weight of the water displaced. This is known as Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the submerged object.
If an object has the same density as the fluid it is submerged in the object will always?
Will always float with the top surface level with the water
How much more does an object weigh after it has been submerged out of water?
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
Why does the object apparently loss weight when completlely submerged in water?
An object will appear to lose weight when completely submerged in water due to the buoyant force acting on it. This force is equal to the weight of the water displaced by the object, causing it to feel lighter in water compared to in air.
How does the volume of a fully submerged object compare with the volume of water displaced?
The volume of a fully submerged object is equal to the volume of water it displaces. This is known as Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the water displaced by the object.
How do you calculate the buoyant force when given the air weight of an object's weight when submerged?
To calculate the buoyant force acting on an object submerged in water, you can use the formula: Buoyant force = Weight of the water displaced = Weight of the object in air - Weight of the object in water. This formula considers that the buoyant force is equal to the weight of the water displaced by the object.
Explain how the buoyant force acting on an object placed in water can be measured?
The buoyant force acting on an object placed in water can be measured by finding the difference between the weight of the object in air and the apparent weight of the object when submerged in water. This difference is equal to the buoyant force acting on the object, which is also equivalent to the weight of the water displaced by the object. By measuring these weights, one can determine the buoyant force acting on the object.
What happens to the buoyant force on an object as is lowered into water?
As the object is lowered into water, the buoyant force acting on it increases because more of the object is submerged in the water, displacing a greater volume of water. This increase in buoyant force helps to counteract the gravitational force acting on the object, making it easier to hold or push the object deeper into the water.
What is volume of the displaced wate is equal to?
The volume of water displaced is equal to the volume of the object submerged in water. This is known as Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the water displaced by the object.
How can you tell if an object will float in water from its gravity?
You can determine if an object will float in water by comparing its density to the density of water. If the object is less dense than water, it will float; if it is more dense, it will sink. The buoyant force acting on the object is determined by the density of the object and the density of the fluid it is submerged in.
