depend on the frequency of the incident light. The maximum energy of emitted electrons is given by the equation E = hf - φ, where E is the maximum energy, h is Planck's constant, f is the frequency of the incident light, and φ is the work function of the metal.
Let the work function of a metal be W. Let C be a constant of the dimension of energy. if Kis the maximum kinetic energy of an electron then.......W=C-K..... (K HERE IS THE ENERGY SUPLIED BY A PHOTON TO THE ELECTRON)
The device you are referring to is a photoelectric cell or a photodiode. When light shines on the metal surface of these devices, electrons are emitted in a process called the photoelectric effect, which generates an electric current.
In the photoelectric effect, light (photons) ejects electrons from a material's surface, creating an electric current. The energy of each photon must exceed the material's work function for electrons to be emitted. The intensity of light affects the number of electrons emitted, while the frequency determines the kinetic energy of the emitted electrons.
Increasing the intensity of light results in more photons hitting the metal surface, which can increase the number of electrons emitted through the photoelectric effect. This can lead to a higher current of ejected electrons being generated.
Electrons are ejected from a metal surface when it is exposed to light of sufficient energy. This phenomenon is known as the photoelectric effect. The energy of the incident light is absorbed by the electrons, causing them to be emitted from the metal surface.
Let the work function of a metal be W. Let C be a constant of the dimension of energy. if Kis the maximum kinetic energy of an electron then.......W=C-K..... (K HERE IS THE ENERGY SUPLIED BY A PHOTON TO THE ELECTRON)
The device you are referring to is a photoelectric cell or a photodiode. When light shines on the metal surface of these devices, electrons are emitted in a process called the photoelectric effect, which generates an electric current.
Photoelectric phenomenon
In the photoelectric effect, light (photons) ejects electrons from a material's surface, creating an electric current. The energy of each photon must exceed the material's work function for electrons to be emitted. The intensity of light affects the number of electrons emitted, while the frequency determines the kinetic energy of the emitted electrons.
Increasing the intensity of light results in more photons hitting the metal surface, which can increase the number of electrons emitted through the photoelectric effect. This can lead to a higher current of ejected electrons being generated.
Electrons are ejected from a metal surface when it is exposed to light of sufficient energy. This phenomenon is known as the photoelectric effect. The energy of the incident light is absorbed by the electrons, causing them to be emitted from the metal surface.
Yes, exposure to blue light can cause the photoelectric effect in cesium, leading to the emission of electrons. Blue light has enough energy to overcome the work function of cesium, which allows electrons to be emitted from its surface.
High-frequency light can cause electrons to be emitted from a metal's surface through the photoelectric effect. However, if the energy of the photons is still not high enough to overcome the metal's work function (the minimum energy needed to release an electron), then electrons cannot be emitted.
The work function of copper is the minimum amount of energy needed to remove an electron from its surface. A lower work function means it is easier for electrons to be emitted from the surface of copper.
i have the same question on my test haha for me, the answers are: a) The number of electrons ejected per second b) the maximum kinetic energy of the ejected electrons c) the threshold frequency of the ejected electrons d) the time lag between the absorption of blue light and the start of emission of the electrons e) none of these A the number of electrons ejected per second,,,,, correct answer
Yes, exposure to red light can cause the emission of electrons from cesium through the photoelectric effect. Red light carries enough energy to excite electrons in the cesium atoms, allowing them to overcome the binding energy and be emitted from the surface.
Electrons are emitted from a metal surface when the energy of the incident photons is great enough to overcome the work function of the metal. This minimum energy required is equivalent to a certain threshold frequency, known as the threshold frequency. Electrons can only be emitted when the frequency of the incident radiation is greater than this threshold frequency because lower frequency photons do not possess enough energy to overcome the work function and release electrons from the metal surface.