It happens because of Newton's 3rd law of motion: Every action has an equal and opposite reaction. The reason that the "kick" is so variable based on gun type is that the force involved is controlled by the formula F=MA or Force=Mass times Acceleration (AKA Newton's 2nd law).
If you have a .22 caliber long rifle round you are looking at perhaps 40 grains of lead (1 grain is about 2 thousandths of an Oz.) and it is leaving the barrel at perhaps 1100 feet per second (FPS). In other words, the bullet went from 0 FPS to 1100 FPS in the fraction of a second that it took to go down the length of the barrel. I won't bore you with the math but that movement represents an acceleration. When you multiply that acceleration times the mass of the bullet (40 grains) it tells you what the force was that caused that acceleration. That force is what you feel in the gun recoil.
A "30 odd six" (30.06) rifle uses a much bigger chunk of lead for the bullet - perhaps 150 grains or more and it flies out of the barrel at something like 3000 FPS. As a result, the force is much higher (still because of F=MA) and thus so is the recoil/"kick".
That only happens if something with mass shoots out of the front end, such as a bullet or some gases. When that happens, the stuff that shoots forward carries forward momentum, so something has to carry backward momentum in order to keep the sum at zero. That's usually the gun itself.
By conservation of momentum, the momentum of the gun and bullet system before firing must equal the total momentum after firing. Therefore, the velocity at which the gun recoils can be calculated by using the equation: (mass of bullet * velocity of bullet)/mass of gun = velocity of gun. Substituting the values given: (0.06 kg * 500 m/s) / 5 kg = 6 m/s.
The total momentum of the bullet and the gun before firing is zero, as the gun and the bullet are at rest. Momentum is the product of mass and velocity, and since both the gun and the bullet are not moving, their momentum is zero.
Compression waves resulting from the firing of a gun are in fact high-pressure sound waves that propagate through the air. These waves are responsible for the loud noise heard when a gun is fired.
When a gun is fired, the bullet propels forward with a certain momentum due to the force applied by the expanding gases in the gun barrel. According to the principle of momentum conservation, the gun must also experience an equal but opposite momentum in the backward direction. This backward momentum causes the sensation of "kick" felt by the shooter as the gun recoils.
When a bullet is fired from a gun, Newton's third law is applied as the bullet and the gun experience equal and opposite forces. The force pushing the bullet out of the gun is equal to the force pushing the gun backward, causing recoil. This relationship between the bullet and the gun follows the principle of momentum conservation.
The plural of recoil is recoils. As in "the gun recoils quite heavily".
Yes.
By conservation of momentum, the momentum of the gun and bullet system before firing must equal the total momentum after firing. Therefore, the velocity at which the gun recoils can be calculated by using the equation: (mass of bullet * velocity of bullet)/mass of gun = velocity of gun. Substituting the values given: (0.06 kg * 500 m/s) / 5 kg = 6 m/s.
A gun recoils when fired due to the need to eject the casing and to recycle the pent up gas
There is a part almost all guns called the extractor that, like its name implies, extracts the shell when the bolt of the gun recoils back.
They are exactly equal. The bullet travels faster, and weighs less. The gun recoils more slowly, but weighs much more.
A firing squad?
gun shop, gun show
its a gun thats why
A gun recoils when bullet is fired off the gun.A swimmer pushes the water when he moves forward.
no
A Paixhans gun is an early naval gun for firing explosive shells.