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A light bulb is nothing more than a piece of wire inside an evacuated (gasless) glass envelope. Light is heat, and the wire is made of such materials to promote great heat to develop quickly. Removing all gasses from the glass envelope makes sure that the wire doesn't just burn - instead, it glows with bright light.
Now, it uses a LOT of energy, transforming it into heat and light. As such, it is an effective current limiter - in a conductor, heat equals resistance.
Calculate it and you will see - a 100W light bulb at 230V will have to use around 0.45A to generate that much power, and in order for it to allow exactly this much, it needs to be a resistor (a 500ohm resistor, to be precise).
230V / 500ohm = 0.46A, and 0.46A * 230V = 105.8W
And that is why a light bulb is an effective resistor.
What else can I help you with?
How would you make a bulb in a circuit shine with a fainter light?
You can make a bulb shine with a fainter light by reducing the voltage supplied to the circuit. This can be done by adding a resistor in series with the bulb to limit the current flowing through it, or by using a dimmer switch to adjust the voltage. Decreasing the power to the bulb will result in a dimmer light output.
How does the electrical resistance of an object change - If a light bulb has X ohms of resistance three of those light bulbs in the same circuit in series have less resistance?
The resistance of a light bulb is inversely proportional to its temperature, i.e. a cold bulb has less resistance than a hot bulb. As a result, if you connect three bulbs in series to the same voltage used for one, they will each receive one third of the original voltage, causing them to use less power, causing them to generate less heat, causing them to have less resistance. If you measure the current in the circuit, there will be slightly more than one third of the original current. Given the same voltage, that means that each bulb has less resistance than originally measured, as expected. This characteristic of light bulbs is why they tend to blow out at turn-on. The starting current and power is higher than in the steady state case. You can make a bulb last much longer if you provide a soft start circuit that ramps up the voltage over a short period of time.
There are two light bulbs in a circuit wired in parallel a third bulb is added what is the effect on tolal resistance of adding the third bulb?
Adding any additional element in parallel will reduce the combined resistance. Do some sample calculations to get a "feel" for this: Total resistance (R) is calculated as 1/R = 1/R1 + 1/R2 + 1/R3... In other words, take the reciprocal of the individual resistances, add them, and then take the reciprocal of the result.
When more light bulbs are added in parallel to a circuit what happens to the total resistance of the circuit?
When more light bulbs are added in parallel to a circuit, the total resistance of the circuit decreases. This is because in a parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. More paths for current to flow mean less overall resistance in the circuit.
How could you make a light bulb in a circuit brighter?
-- Without changing the bulbs, increase the voltage of the battery or power supply. -- If the bulbs are in series, take one out of the circuit, and replace it with a piece of wire. -- Replace incandescent bulbs with others whose filaments have lower resistance. -- Replace incandescent bulbs with fluorescent tubes. -- Replace incandescent bulbs with LEDs.
how to use circuit in sentence?
to complete the circuit you have to add 1 light bulb.
How would you make a bulb in a circuit shine with a fainter light?
You can make a bulb shine with a fainter light by reducing the voltage supplied to the circuit. This can be done by adding a resistor in series with the bulb to limit the current flowing through it, or by using a dimmer switch to adjust the voltage. Decreasing the power to the bulb will result in a dimmer light output.
If you add an extra battery to a circuit containing a bulb how will this affect the bulb?
The bulb becomes brighter unless it is too much till it shot-circuits.
What happens when you add a resistor to a series circuit with a light bulb?
As you add more bulbs to a series circuit that means that the bulbs are in series to one another, therefore the total resistance is the sum of the individual resistance of the bulbs. If you add bulbs of the same resistance,then the rate at which the resistance changes will increase in a constant manner provided the current source is not altered. For instance if the bulb you are using is rated 20v,60w, then the current passing via the bulbs in series is the square of the voltage divided by the power in this case the current is approximately 7amperes.
What will happen to the resistance and the brightness if you add a light bulb to the circuit?
If a rheostat is connected in parallel with a light bulb, the setting of the rheostat should have no effect on the performance of the light bulb, as long as the power supply is able to maintain its output voltage and deliver the current demanded by their parallel combination.
How does the electrical resistance of an object change - If a light bulb has X ohms of resistance three of those light bulbs in the same circuit in series have less resistance?
The resistance of a light bulb is inversely proportional to its temperature, i.e. a cold bulb has less resistance than a hot bulb. As a result, if you connect three bulbs in series to the same voltage used for one, they will each receive one third of the original voltage, causing them to use less power, causing them to generate less heat, causing them to have less resistance. If you measure the current in the circuit, there will be slightly more than one third of the original current. Given the same voltage, that means that each bulb has less resistance than originally measured, as expected. This characteristic of light bulbs is why they tend to blow out at turn-on. The starting current and power is higher than in the steady state case. You can make a bulb last much longer if you provide a soft start circuit that ramps up the voltage over a short period of time.
What is the current in the circuit contains two 1.5 volt batteries and 6 ohm light bulb?
If the two batteries are in series, add the voltages. Then use Ohm's Law to calculate the current (that is, divide the voltage by the resistance).
How is adding a ammeter to a circuit different from adding a light bulb?
When you add a light bulb, you are adding a load, which performs a function - in this case, it converts electrical energy to light and heat energy. When you add an ammeter, most of the time you intend to measure the current in the circuit, which is the function of the ammeter. Thus the two electrical components differ in their function and does different things when added to a circuit.
There are two light bulbs in a circuit wired in parallel a third bulb is added what is the effect on tolal resistance of adding the third bulb?
Adding any additional element in parallel will reduce the combined resistance. Do some sample calculations to get a "feel" for this: Total resistance (R) is calculated as 1/R = 1/R1 + 1/R2 + 1/R3... In other words, take the reciprocal of the individual resistances, add them, and then take the reciprocal of the result.
When more light bulbs are added in parallel to a circuit what happens to the total resistance of the circuit?
When more light bulbs are added in parallel to a circuit, the total resistance of the circuit decreases. This is because in a parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. More paths for current to flow mean less overall resistance in the circuit.
What happens in a series circuit if the resistance is halved?
If you add a second resistor, the resistance of series circuit will increase.
If their is more bulbs in a circuit does the resistance increase?
Yes. Each light bulb is just another resistor in a series circuit, where you add the individual resistances to get the total resistance (unless the bulbs are set up in parallel, where adding a second identical light bulb would cut the total resistance in half).
