Force can be real or vector. Force in general is a quaternion consisting of a real and a vector component. Force is" considered a vector quantity" because force is assumed to "have a direction and only vectors have directions". The universe is made up of reals/scalars and vectors called quaternions. Quaternions consist of a real r and three vectors, v=ix +jy + kz, q=r + v. Scientists have defined forces incorrectly because they have neglected the real or scalar forces in science. For example, consider Newton's gravitational potential energy, E=-mu/r. The real derivative of the potential energy is dE/dr = mu/r^2=mv^2/r, a real/scalar force. This is a force but it is not a vector force , it is a real or scalar force. The Gradient of E is a vector force Del -mu/r= mu/r^2( R/r) = mv^2/r (R/r)=mv^2/r R'. The gradient is a vector derivative of the real potential energy and produces a vector force. The real derivative produces a real force. Scientists including Newton were not clear about this difference and it is still the case. Consider f=qvB where v and B are the vector velocity and the vector B-field. The force is f=-qv.B + qvxB. The vector force is recognized as the Lorentz force, the real force qv.B is not recognized at all. It is the real force in the direction of the magnetic field. Here you see the real force has a direction it is parallel to the B field, but it is not a vector force it is a real force. The vector force qvxB is a vector force perpendicular to the B field. The quaternion force is f=qvB= -qv.B + qvxB = -qvbcos(x) + qvBsin(x)T'. Force can be real or vector. Force in general is a quaternion consisting of a real and a vector component.
No, electric potential is a scalar quantity, not a vector quantity.
No, the velocity vector of a charged particle is not affected by the electric field if it is perpendicular to the field. The electric force acting on the particle is zero in this case because the force is given by the product of charge and the component of electric field parallel to the velocity vector.
Light is characterized by its electric vector because its interactions with matter are primarily through the electric field. The magnetic field of light comes into play when dealing with certain materials or under specific conditions, such as in radio waves or at high frequencies, but in general, the electric field of light is more prominent in its interactions with matter.
Scalar
Electric flux is a scalar quantity, as it represents the amount of electric field passing through a given area. It does not have a direction associated with it, unlike vector quantities.
No, electric potential is a scalar quantity, not a vector quantity.
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
Scaler. The electric field is its vector counterpart.
No, the velocity vector of a charged particle is not affected by the electric field if it is perpendicular to the field. The electric force acting on the particle is zero in this case because the force is given by the product of charge and the component of electric field parallel to the velocity vector.
Light is characterized by its electric vector because its interactions with matter are primarily through the electric field. The magnetic field of light comes into play when dealing with certain materials or under specific conditions, such as in radio waves or at high frequencies, but in general, the electric field of light is more prominent in its interactions with matter.
Scaler. Its vector counterpart is the electric field.
Scalar
Electric flux is a scalar quantity, as it represents the amount of electric field passing through a given area. It does not have a direction associated with it, unlike vector quantities.
Examples of vector quantity are displacement, velocity, acceleration, momentum, force, E-filed, B-field, torque, energy, etc.
Yes, it is.
Charles Darwin
From an electric field vector at one point, you can determine the direction of the electrostatic force on a test charge of known sign at that point. You can also determine the magnitude of the electrostatic force exerted per unit charge on a test charge at that point.