It is only zero if there is no current in the conductor. When there is a current traveling through a long copper wire, there is an electric field helping the electrons over come the resistance. Because copper is a good conductor however, the electric field does not have to be very strong.
That being said, if you have a piece of wire or any conductor and there is no battery or anything causing current to travel through it the electric field will always be zero inside.
The easiest way to understand why is to imagine that there was an electric field in the conductor. If there was an electric field it would cause electrons to move, and moving of the electrons would result in the cancellation of the electric field.
Here is a concrete example.
Imagine a thick copper wire stretched from the left to the right. Image we were somehow able to pick electrons out of the left side and place them in the wire at the right end. For a very short moment after we placed the electrons in the right end there would be an electric field running through the entire length of the wire. The electric field would exert a force on every single electron in the copper wire and it would be toward the left. That is because they would be attracted to the exposed protons at the left end and be repelled by the lone electrons at the right end. Also, because of the electric field all the protons would feel a force towards the right because they would be attracted to the lone electrons at the right and repelled by the exposed protons at the left. The only charges that would move however would be the electrons that are free to move. As it happens, in copper, there is about one free electron per copper atom. Those free electrons would be shifted toward the left and the result would be that the exposed protons at the left would be "covered" up or neutralized and the lone electrons at the right would no longer be alone and therefor neutralized.
To understand this process better imagine a long hose running from the left to the right and completely filled with marbles. Imagine pulling a marble out of the left end and holding it at or near the right end. The marble being held at the right end represents a lone electron and the empty space at the left end represents an exposed positive charge. Now if you were to to stick the marble into the right end, all of the marbles would shift to the left. As a result there would be no more empty space at the left end and no longer a lone marble at the right end.
In the same way, because of the electric field in the copper wire, all the free electrons would shift to the left and the electric field would disappear because there would be no more exposed charges at either end. As it happens, this process would only take a fraction of a nanosecond.
As a side note, what a battery does is force exposed positive charges to be at one end of a wire and lone electrons to be at the other. When the free electrons in the wire experience the electric field and shift, it is the "job" of the battery to replace the exposed positive charge and the lone electrons. In a normal circuit however there is a resistor at some point along the wire in order to reduce the rate of flow of electrons to something the battery can handle. The vast majority of the electric field/voltage ends up being across the resistor.
So to recap, there is no electric field in a conductor because if there was, the free electrons would immediately shift to eliminate the electric field.
At the risk of complicating matters I need to add that if the initial electric field in the conductor was not caused by charges in the conductor but by charges outside and distant from the conductor, the free electrons would still shift to neutralize the electric field but they would end up creating lone negative electrons and exposed positive protons at different places on the surface of the conductor to do it.
The electric field created by the electrons shifting ends up exactly canceling the electric field created by the distant charges.
A Wikipedia article that deals with this subject somewhat is in the related links section below.
Electric filed due to uniformly charged spherical shell at a point inside the shell, the total flux crossing the Gaussian sphere normally in an outward direction. there is no charge enclosed by the gaussian surface, according to Gauss law
* The electric charge is uniformly distributed along the surface.* An object in the inside feels the same force from any solid angle at opposite sides. For instance, if it is twice as far away from one side than to the other, along a certain solid angle (say, 1 square degree) there will be 4 times as much charge on side than on the opposite side. This is compensated by the fact that the force per unit charge, on the far side, will also get reduce by the same factor - in this example, 4.
This information explanation can be formalized via calculus.
because all of the charged particles are at the edges
charge always resides on the surface of the conductors charge inside the conductor is zero. so according to Gauss there is no flux inside it.as there is no flux so there is no electric field
It is zeo because the sphere is round, which doesn't give out electrical pulse.
If the charge is evenly distributed over the sphere ... as it would be if the sphere is a conducting material ... then the electric field at the center of the sphere is zero. If the sphere is not a conductor and the charge hasn't been applied to it symmetrically, then the magnitude and direction of the electric field at the center depend on every little detail of exactly how it's distributed on the sphere.
The direction of the electric field produced by a charged object is never parallel to the object's surface. It's in the direction of a radius that begins at the object's center of charge.
-- the product of the magnitudes of the charges on the objects -- the distance between the 'center of charge' of the two objects
If the object is homogeneous, its center of mass is in its geometrical center. And if it is small compared to Earth, its center of gravity is, for all practical purposes, its center of mass.
It is the center of the imaginary sphere to which the mirror belongs.
A spherical conductor with a radius of 14.0 cm and charge of 26.0 microcoulombs. Calculate the electric field at (a)r=10.0cm and (b)r=20.0cm and (c)r=14.0 from the center.
If the charge is evenly distributed over the sphere ... as it would be if the sphere is a conducting material ... then the electric field at the center of the sphere is zero. If the sphere is not a conductor and the charge hasn't been applied to it symmetrically, then the magnitude and direction of the electric field at the center depend on every little detail of exactly how it's distributed on the sphere.
Should be zero.
From Gauss's Law, Electric Field inside is 0, and it's electric flux is equal to Qenclosed/Eo, where Eo is the electric vacuum permittivity constant. Also, outside of the sphere, it could be treated as a point charge, where the point lies at the center of the shell and has a charge equal to the total charge of the shell.
Each atom has a charged center (nuclei) with the positive electric charge and electron(s) rotates around this center with the negative electric charge.
The direction of the electric field produced by a charged object is never parallel to the object's surface. It's in the direction of a radius that begins at the object's center of charge.
The Nucleus
No , a static charge will always appear to be concentrated around the edge of the object....
the centre of the sphere.
Water molecules are not spherical, they are V shaped with an Oxygen in the center and a Hydrogen atom on each side of it.
-- the product of the magnitudes of the charges on the objects -- the distance between the 'center of charge' of the two objects
The most curved mirrors are spherical mirrors. The centre of curved surface is called center of curvature. There are two kinds of spherical mirrors. Concave and convex mirror.