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Because work done is equal to the force times the distance travelled IN THE DIRECTION of the force.
Distance travelled in an oblique direction can be decomposed into two components: s*cos(x) in the direction of the force and s*sin(x) in a direction perpendicular to it (where x is the angle between the force and the resultant motion). Motion in a perpendicular direction is NOT work done by the force, which leaves s*cos(x). Multiply by the force (as required) and you have your answer.
What else can I help you with?
What is the formula for calculating the work done by a constant force?
The formula for calculating the work done by a constant force is: Work Force x Distance x cos(), where is the angle between the force and the direction of motion.
How do you find the angle in the work done?
You measure it. Depending on the information provided, you can also calculate it, for example using trigonometry. ======================== Work done= Force vector . Displacement vector=Force*displacement*cos a, where a is the angle between the force and the displacement. So you have the values of work force and displacement then you can do the cosine inverse of the ratio of work done to the product of the force and displacement. That will give you the angle.
How much work is done when an 8 N moves a block 7m?
The work done is calculated using the formula: work = force x distance x cos(theta). Given the force (8 N) and distance (7 m), the work done is 56 N·m.
How is the work done on an object calculated?
Work done on an object is calculated by multiplying the force applied to the object by the distance the object moves in the direction of the force. The formula for work done is: work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion.
How much work is done in lifting a 50kg object to height of 5m?
The work done in lifting a 50kg object to a height of 5m is 2450 Joules, calculated using the formula: Work = force x distance x cos(theta).
What is the formula for calculating the work done by a constant force?
The formula for calculating the work done by a constant force is: Work Force x Distance x cos(), where is the angle between the force and the direction of motion.
What can be said about a situation in which work done is negative?
the formula F.S cos angle is used (the dot product) so if angle is 0,cos angle=1 hence work done is positive and maximum if angle is 90 so cos 90 is 0 hence work done is minimum if work done is negative the angle is 180 The work done by friction is always negative (opposite the force) Since work is force x displacement, a negative value for work could mean that the displacent was negative
How do you find the angle in the work done?
You measure it. Depending on the information provided, you can also calculate it, for example using trigonometry. ======================== Work done= Force vector . Displacement vector=Force*displacement*cos a, where a is the angle between the force and the displacement. So you have the values of work force and displacement then you can do the cosine inverse of the ratio of work done to the product of the force and displacement. That will give you the angle.
How much work is done when an 8 N moves a block 7m?
The work done is calculated using the formula: work = force x distance x cos(theta). Given the force (8 N) and distance (7 m), the work done is 56 N·m.
How is the work done on an object calculated?
Work done on an object is calculated by multiplying the force applied to the object by the distance the object moves in the direction of the force. The formula for work done is: work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion.
How much work is done in lifting a 50kg object to height of 5m?
The work done in lifting a 50kg object to a height of 5m is 2450 Joules, calculated using the formula: Work = force x distance x cos(theta).
What is the value of work done on an object when a 70-newton force moves it 9.0 meters in the same direction as the force?
The work done on the object is calculated using the formula: work = force * distance * cos(theta), where theta is the angle between the force and the direction of motion. Since the force and distance are in the same direction, cos(0) = 1, and the work done is 70 N * 9.0 m = 630 joules. So, the value of work done on the object is 630 joules.
How much workdone is done when a weight of 10n is raised 2m vertically?
The work done is calculated using the formula: Work = Force × Distance × cos(θ). In this case, the force is 10 N, the distance is 2 m, and the angle θ is 0 degrees since the force and distance are in the same direction. Therefore, the work done is 10 N × 2 m × cos(0°) = 20 Joules.
How did you determined that work is done?
Work is done when a force acts upon an object to cause it to move in the direction of the force. Mathematically, work done is calculated by the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. So, when a force is applied on an object to move it a certain distance, work is done.
To calculate work done on an object .?
Work done on an object is calculated by multiplying the force applied to the object by the distance the object moves in the direction of the force. The formula for work done is: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. Work is typically measured in joules (J).
What is the formula for calculating work done when a force is applied in the direction of motion, involving the product of the force and the displacement, represented by the keyword r cross f?
The formula for calculating work done when a force is applied in the direction of motion is W F d cos(), where W is the work done, F is the force applied, d is the displacement, and is the angle between the force and the direction of motion.
What is the formula of calculating the amount of work done by force?
The simplest formula is: work = force x distance. This formula applies when the force is constant, and force and movement are in the same direction. Otherwise, the dot product should be used. This still assumes that the force is constant. If it isn't, an integral is used.It will be nice to use this in common. Work = Force vector . displacement vectorSO W = F s cos@Here @ is the angle between the force and displacement
