Copper is the better conductor. The only materials that are better conductors than copper are either very expensive (such as gold and silver), or superconductors that only work at cryogenic (supercold) temperatures.
A copper wire will allow more electric current to pass through compared to a steel wire of the same thickness and length. This is because copper has lower resistance to the flow of electricity, resulting in better conductivity.
The current in the copper wire will be higher than the current in the germanium wire. This is because copper has lower resistance compared to germanium, allowing more current to flow for a given voltage. Germanium has higher resistance due to its crystal structure, which hinders current flow.
A thicker copper wire will allow more electric current to pass through because it has lower electrical resistance. Thinner wires have higher resistance due to increased resistance per unit length. This causes more voltage drop and heat dissipation in the wire, limiting the amount of current that can flow through.
The thickness of the wire (resistance) and length of the wire can affect the brightness of the bulb. Thicker wire has less resistance, allowing more current to flow and producing a brighter bulb. Shorter wire lengths also reduce resistance, resulting in a brighter bulb due to more current flowing through it.
Increasing the thickness of the lens generally decreases the focal length, while decreasing the thickness increases the focal length. This is due to the way light rays bend and converge or diverge as they pass through different thicknesses of the lens. The relationship between lens thickness and focal length is determined by the lens's refractive index and curvature.
A copper wire will allow more electric current to pass through compared to a steel wire of the same thickness and length. This is because copper has lower resistance to the flow of electricity, resulting in better conductivity.
It depends on the material of the cable (aluminum or copper) and the gauge of the cable. (Thickness). And on the current you intend it to carry.
The current in the copper wire will be higher than the current in the germanium wire. This is because copper has lower resistance compared to germanium, allowing more current to flow for a given voltage. Germanium has higher resistance due to its crystal structure, which hinders current flow.
capicity=length*width*thickness
A point has no length, width, or thickness. A line has infinite length but no width or thickness. A plane has infinite length and width but no thickness.
A thicker copper wire will allow more electric current to pass through because it has lower electrical resistance. Thinner wires have higher resistance due to increased resistance per unit length. This causes more voltage drop and heat dissipation in the wire, limiting the amount of current that can flow through.
The thickness of the wire (resistance) and length of the wire can affect the brightness of the bulb. Thicker wire has less resistance, allowing more current to flow and producing a brighter bulb. Shorter wire lengths also reduce resistance, resulting in a brighter bulb due to more current flowing through it.
Copper or aluminum AWG. As for gauge and such, it depends on how much amperage you have running through it, and the length of wire.
Length IS a dimension (in space). It has no thickness.
To calculate the weight of a copper cathode sheet, you would first need to know the dimensions of the sheet (length, width, and thickness). Then, you can use the formula: weight = density of copper x volume of the sheet, where the density of copper is 8.96 g/cm3. Multiply the volume (length x width x thickness) by the density to find the weight in grams.
Time has no length, width or thickness.
Increasing the thickness of the lens generally decreases the focal length, while decreasing the thickness increases the focal length. This is due to the way light rays bend and converge or diverge as they pass through different thicknesses of the lens. The relationship between lens thickness and focal length is determined by the lens's refractive index and curvature.