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How much work is done in lifting a 50kg object to height of 5m?

The work done in lifting a 50kg object to a height of 5m is 2450 Joules, calculated using the formula: Work = force x distance x cos(theta).


What is the relationship between work and gravitational potential energy?

Work = energy (by the Work-Energy Equivalence Theorem).The work done in lifting an object shows up as the gravitational potential energy of the object: W = mgh, where W is the work done; m is the object's mass; g is the acceleration due to Earth's gravity; and h is the height to which the object is lifted. (This assumes that the lifting is done near Earth's surface, with gravity effectively constant.)ALL Credit goes to Argent at yahoo answers


How can doing work on a object increase its potential energy?

When work is done on an object by applying a force over a distance, the object gains potential energy. For example, lifting an object against gravity increases its height and potential energy due to the work done in lifting it. This increase in potential energy is a result of the energy transferred to the object from the external force applied to it.


If you lift 1600 meters straight up how much work did you do?

To calculate the work done when lifting an object, you can use the formula: work = force × distance. The force required to lift an object is equal to its weight, which is mass × gravity. So, you would need to know the mass of the object to calculate the work done when lifting it 1600 meters.


What is gravitationla potential energy?

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. The potential energy is based on the object's height above a reference point and is related to the work done in lifting or lowering the object in the gravitational field. The higher an object is lifted, the greater its gravitational potential energy.

Related Questions

How much work is done in lifting a 50kg object to height of 5m?

The work done in lifting a 50kg object to a height of 5m is 2450 Joules, calculated using the formula: Work = force x distance x cos(theta).


What is the relationship between work and gravitational potential energy?

Work = energy (by the Work-Energy Equivalence Theorem).The work done in lifting an object shows up as the gravitational potential energy of the object: W = mgh, where W is the work done; m is the object's mass; g is the acceleration due to Earth's gravity; and h is the height to which the object is lifted. (This assumes that the lifting is done near Earth's surface, with gravity effectively constant.)ALL Credit goes to Argent at yahoo answers


How can doing work on a object increase its potential energy?

When work is done on an object by applying a force over a distance, the object gains potential energy. For example, lifting an object against gravity increases its height and potential energy due to the work done in lifting it. This increase in potential energy is a result of the energy transferred to the object from the external force applied to it.


If you lift 1600 meters straight up how much work did you do?

To calculate the work done when lifting an object, you can use the formula: work = force × distance. The force required to lift an object is equal to its weight, which is mass × gravity. So, you would need to know the mass of the object to calculate the work done when lifting it 1600 meters.


What is gravitationla potential energy?

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. The potential energy is based on the object's height above a reference point and is related to the work done in lifting or lowering the object in the gravitational field. The higher an object is lifted, the greater its gravitational potential energy.


How many joules of work are done when a 20 newton is lifted 5 meters off of the floor?

The idea here is to multiply the force by the distance.


What is The work done holding a 50 kg object at a height of 2 m above the floor for 10 seconds?

The answer is 0. If you used the formula of =>mgh, you would get a value which would be wrong. The question is a trick question. There is no work done in 'holding' an object but work would be done in 'lifting' an object. Hence, 0. ~Dartz


How much work is done in lifting a 20 kg object through a distance of 0.40 m Use g 10 ms?

The work done in lifting an object is given by the formula: work = force x distance. The force required to lift an object against gravity is equal to the weight of the object, which is mass x gravity. So, work = (20 kg x 10 m/s^2) x 0.40 m = 80 J.


Do you do work when you lift it from the floor to a shelf?

Yes, work is done when you lift an object from the floor to a shelf. Work is the exertion of a force over a distance, and in this case, the force is applied to overcome gravity in lifting the object to a higher position.


How are work and potential energy related?

Work is the transfer of energy from one system to another, often resulting in a change in an object's potential energy. When work is done on an object against a force (e.g., lifting an object against gravity), its potential energy increases. Conversely, when work is done by a force (e.g., object falling due to gravity), potential energy decreases.


Enumerate the situations where work is present?

Work is present in situations where a force is applied to an object, and the object moves in the direction of the force. Examples include lifting a weight, pushing a cart, or pulling a sled. Additionally, work is done when energy is transferred, such as when electrical energy powers a device. Importantly, no work is done if the object does not move, regardless of the force applied.


The work done in lifting 30kg of bricks to a height of 20m on a building under construction is?

The work done in lifting an object can be calculated using the formula ( W = mgh ), where ( W ) is the work done, ( m ) is the mass (30 kg), ( g ) is the acceleration due to gravity (approximately ( 9.81 , \text{m/s}^2 )), and ( h ) is the height (20 m). Substituting the values, ( W = 30 \times 9.81 \times 20 ), which equals 5886 Joules. Thus, the work done in lifting the bricks is 5886 Joules.