If the ball ended 40 m from the cliff after 4 seconds, the original horizontal
velocity was 10 m/s. You can calculate the height assuming standard gravity
acceleration (g = 9.81 m/s2) and zero original vertical velocity, by calculating the final downward velocity vy2, vy2 = a x t = 9.81 m/s2 x 4 s = 39.24 m/s and from this the average velocity, vav = 39.24 m/s / 2 =19.62 m/s and multiply by 4 s, 19.62 m/s x 4 s = 78.48 m.
You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 3 seconds?
velocity means how fast it's going and the direction. so wat was the direction? but the speed is .............120 m/s
The answer is ZERO. After 4 sec. the ball is at rest.
Acceleration of gravity is 9.8 meters per sec2 downward.
V = Vi + a t = (30) + (-9.8) (2) = 30 - 19.6 = 10.4 meters per second, up
no mameees
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
yes, i just test right now
False, provided the drop occurs no sooner than the throw, and the ground is flat .
No. They both hit the ground at the same time. This is because the VERTICAL component of velocity in both cases is the same.
No. They both hit the ground at the same time, because the VERTICAL component of velocity in both cases is the same.
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
10 m/s
Answer: 3 seconds
64 METERSA+
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
Answer: 44 meters
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
If it was thrown horizontally, it had an initial velocity of 10 meters/sec parallel to the ground. (It traveled 40 meters in 4 secs with no acceleration. x=vt) It also took 4 secs to travel vertically. It started with a vertical velocity of 0 m/s. Using x=v0 + (1/2) a t2 a = -g ( Acceleration due to gravity 9.8m/s2) x=0-(1/2)g*16 = -8 * 9.8 = -78.4 m It fell 78.4 meters before coming to a stop.
"3.2" or "3.20" please put all of that
22.35294117647059
It doesn't matter whether the object is thrown down, up, horizontally, or diagonally. Once it leaves the thrower's hand, it is accelerated downward by an amount equal to acceleration of gravity on the planet where this is all happening. On Earth, if you throw an object horizontally, it accelerates downward at the rate of 9.8 meters per second2 ... just as it would if you simply dropped it. Whether it's dropped or thrown horizontally, it hits the ground at the same time.
yes, i just test right now