taking an introductory Computer Science Class, this program that I wrote recently may help you. Basically it asks the user to input a bunch of numbers (1-100). Then, it places the numbers into categories of either 1-10,11-20,21-30, etc. Each "*" represents 5 elements. This program isn't as efficient.. but then again , it it's an introductory Computer Science Class, it'll work and at least give you a sense of direction!
/**
*Design and implement an application that reads a set of integer values in the range of 1 to 100 from the user and
then creates the chart showing how often the values appeared. The chart should look like the one shown below.
It shows how many values fell in the range from 1 to 10, 11 to 20, and so on. Print an asterisk for every five
values in each category. For example, if a category had 17 values, print three asterisks in that row. If a
category had 4 values, do not print any asterisks in that row. Be sure to include two classes StarTable and
StarTablePrgm. Feel free to make the input/output more user friendly.
*/
import java.util.ArrayList;
import java.util.Scanner;
//Margaret Wang creates StarTable Program
public class StarTable
{
private ArrayList<Integer> setOfInt;
//Default Constructor
public StarTable()
{
setOfInt = new ArrayList<Integer>();
}
//Method to read and add the set of integer values
public void addValues()
{
Scanner in = new Scanner(System.in);
System.out.println("Input an integer (1-100). Press enter to input it into the Array. Enter Q to stop adding: ");
String userInput = in.next();
while ( !(userInput.equalsIgnoreCase("Q")))
{
int addInt = Integer.parseInt(userInput);
setOfInt.add(addInt);
userInput = in.next();
}
}
public String printTable()
{
//counts how many numbers fit into each row
int count1 =0;
int count2=0;
int count3=0;
int count4=0;
int count5=0;
int count6=0;
int count7=0;
int count8=0;
int count9=0;
int count10=0;
//searches for the numbers that fit in the ranges
for (int i = 0; i < setOfInt.size(); i++)
{
if (setOfInt.get(i) <= 10)
{
count1++;
}
else if (setOfInt.get(i) <= 20)
{
count2++;
}
else if (setOfInt.get(i) <= 30)
{
count3++;
}
else if (setOfInt.get(i) <= 40)
{
count4++;
}
else if (setOfInt.get(i) <= 50)
{
count5++;
}
else if (setOfInt.get(i) <= 60)
{
count6++;
}
else if (setOfInt.get(i) <= 70)
{
count7++;
}
else if (setOfInt.get(i) <= 80)
{
count8++;
}
else if (setOfInt.get(i) <= 90)
{
count9++;
}
else if (setOfInt.get(i) <= 100)
{
count10++;
}
else
throw new IllegalArgumentException("You have entered an integer that cannot counted");
}
//Creates the Table
String table = "";
for (int a = 0; a < 10; a++)
{
table += a*10 + 1 + "-" + (a+1)*10 + "|";
if (a 9)
{
for (int j = 0; j < count10/5; j++ )
table += "*";
}
table += "\n";
}
return table;
}
}
comparison between histogram equalization and histogram matching?
This is the definition of a histogram: A histogram is a graph showing the intervals and frequencies of a certain topic. That's about all I can give you, because I don't know how to make graphs on here. SORRY!! -belair14, Anna
Yes, you can.
What is a shape of a histogram?
A histogram is basically a bar graph but no spaces in between. That is what I was taught at school a few years ago. But here is a source to check out.
Many people make Java programs, but if you mean who invented the Java programming language it was James Gosling of Sun Microsystems.
1995
How can we make sure (pragmatically) that a class will have no further child classes. Which programming stmt will do this in Java and C++?
Java applets are written in the Java programming language. Java is considered to be one of the oldest and most commonly used programming languages in the world.
You don't. There are hundreds, nay thousands, of programming languages, Java is just one of them. Programming languages are used to make computer programs (software); software is basically what makes computers work.
The first name of the Java Programming was Oak. It then went by the game Green and finally Java from Java coffee.
In programming in general - and that would include Java - that means that you can make corrections and other changes, with a reasonable effort.
If you are going to make an if statement with or, use: Isn't that easy!
Java Card is a Java platform for programming smart cards.
no, Java is not dbms.. Java is a programming language Dbms is database
The Java programming language is a general-purpose computer programming language that is concurrent, class-based, object-oriented, and specifically designed to have as few implementation dependencies as possible. Then you learn java programming language in Pakistan get the best java programming classes at the lowest cost.
The pane in which the Java programming statements are located is called