How do you solve this question 4 plus y equals 18 - y?
Subtract 4 from both sides and add y to both sides. This would give you 2y=14.
Then, divide both sides by 2. y=7.
52,560,000
The way you can get that number is simple:
10 x 0.10 = 1
1 x 60 = 60
60 x 24 = 1,440
1440 x 365 = 525,600
525,600 x 100 = 52,560,000
You see, you start out by multiplying the number of numbers you can count every 10 seconds, you multiple that number by the number of minutes in a hour, you multiple that number by the number of hours in a day, you multiple that number by the number of days in a year, and you multiple that number by 100 years.
So, if you constantly counted by 1 every 1 second, for 100 years, the number you would end up with is 52 billion, 560 hundred thousand.
Solving quadratic equation using the 0 prinicple?
if, for example, 0=x^2+5x+6, then:
0=(x+3)(x+2)
the numbers '3' and '2' must add to give you 5, and multiply to give you 6.
SO:
0=x^2+(a+b)x+(ab)x
0=(x+a)(x+b)
The step-work involved in proving this would be too long and detailed to show here, but the end result is this:
We're given three verticies, defined by the points (x1, y1), (x2, y2), and (x3, y3). We want to use them to define a parabola in this format:
f(x) = ax2 + bx + c
We can find our a, b and c coefficients with the following equations:
a = [y1(x2 - x3) + y2(x3 - x1) + y3(x1 - x2)] / [x12(x2 - x3) + x22(x3 - x1) + x32(x1 - x2)]
b = (y1 - y2) / (x1 - x2) - a(x1 + x2)
c = y1 - a(x12) - b(x1)
Why can't we write equals in place of equals?
You can write "equals".
It would be perfectly fine to say "2 + 2 equals 4".
It's jsut that, it's much more common to use "=", just because it's easier probably.
1/3 - 2/(2y + 1) = 3/y
Provided that y ≠-1/2 and y ≠0,
multiply through by 3y(2y+1) to give
y(2y + 1) - 6y = 9(2y+1)
that is, 2y2 + y - 6y = 18y + 9
or 2y2 - 23y - 9 = 0
The quadratic formula then gives y = [23 ± sqrt{232 - 4*2*(-9)}]/(2*2)
= [23 ± sqrt(601)]/4
so that y = -0.3788 or y = 11.8788
Is 18 x 52 stronger than 10 x 50?
Two numbers multiplied together produce a number. A number is neither strong nor weak.
Is 5 a solution to -3x plus 211?
( -3x + 211 ) is not an equation, so it doesn't have a 'solution'. It's not asking
a question, so it doesn't need an answer.
It's just an expression that stands for a number, and there's no way to tell
what number it stands for until you find out what number 'x' is .
If 'x' is 5, then the expression stands for the number 196 .
If 'x' is 17, then the expression stands for 160 .
If 'x' is 55, then the expression stands for 46 .
If 'x' is something else, then the expression stands for some other number.
How do you factor x2-20 plus 100 equals 0?
I'm guessing you meant to say x2 -20x +100. This equation is in ax2+bx+c=0 (1 is the "a" term, -20 is the "b" term, and 100 is the "c" term. You have to think to yourself, what factors of the "c" term (100) will add to the "b" term (-20) These factors are -10 and -10 because when you add these two terms you get -20 and when you multiply these two terms you get 100. Now your equations should read like this: (x-10)(x-10) = 0 . then you have to get x by itself by adding 10 to both sides. Thus, 10 is your factor.
Whats property is used to solve the equation x plus 5 12?
Without an equality sign it is not an equation