Calculus

5

Y = 7 + 2X - 2X^2

set = to 0

7 + 2X - 2X^2 = 0

arrange in standard quadratic form

2X^2 - 2X - 7 = 0

I am too lazy to factor, so the quadratic equation........

-b +/- sqrt(b^2-4ac)/2a

a = 2

b = -2

c = -7

check with discriminant. b^2 - 4ac

-2^2 - 4(2)(-7) = 60; greater than 1; 2 real roots

-(-2) +/- sqrt[(-2)^2 - 4(2)(-7)]/2(2a)

2 +/- sqrt(60)/4

2 +/- 2sqrt(15)/4

not pretty, just, save factoring, exact

x2 - 9x + 8 = (x-1)(x-8)

The graph is a region of the space on one side or another of the related function. If the inequality is strict then the related function itself is not part of the solution; otherwise it is.

That's going to have a lot to do with what ' x ' is. And any time ' x ' changes,

that whole quantity also changes immediately.

Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question.

Suppose x + y + z = 0

then z = - x - y = -(x + y) . . . . . . (A)

1/x + 1/y + 1/z = 0

implies x, y and z are all non-zero: otherwise the reciprocals are undefined.

then z ≠ 0 implies that x+y ≠ 0 (by (A))

so 1/x + 1/y + 1/[-(x+y)] = 0 (using (A))

so that 1/x + 1/y = 1/(x+y)

ie (x + y)/xy = 1/(x + y)

Now, since x+y ≠ 0, multiply both sides by x+y to give

(x + y)2/xy = 1

or (x + y)2 = xy

x2 + 2xy + y2 = xy

x2 + xy + y2 = 0

so that x = [-y ± sqrt(y2 - 4y2)]/2

= [-y ± y*sqrt(-3)]/2 which is cannot be real if y is real.

(9 of anything) plus (8 of the same thing) = 17 of them

There can be no answer without values for x and y.

9y

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (eg x-squared = x^2).

There is only one cube shape and it is called a cube or a regular hexahedron.

15

1 milliliter equals 0.001 liters

x(x + 2)

The indefinite integral of (6x4-2)2(24x) dx.

The simplest way to do this is to expand the multiplication in the integrand until its a single polynomial comprised of only terms added or subtracted together.

(6x4-2)2=(6x4-2)(6x4-2)=36x8-24x4+4=4(9x8-6x4+1)

(24x)(4(9x8-6x4+1))=96x(9x8-6x4+1)=96(9x9-6x5+x)

From here on out, its simple polynomial antiderivation. The 96 is a constant that can be factored out and ignored. So the antiderivative would be:

96*[9x9/10 - x6 + x2/2] + C

y + 5x = 6 if x = {-1, 0, 1}

No more than 10, as there are only five d suborbitals and each one can only hold two electrons at once.

y=yawn

"y" will double, too.

Substitute the values of x and y in 10x + 7y, thus:

10x + 7y = 10*9 + 7*6 = 90 + 42 = 132