How do you solve second order differential equation with many variables?
I want to solve the following equation:
X''(t)=(`ρ`*Cd*(Vz-Wz)*(Vx-Wx))/Bc
Y''(t)+(`ρ`*Cd*(Vy-Wy)*(Vx-Wx))/Bc
Z''(t)+((`ρ`*Cd*(Vz-Wz)^2)/Bc)+g
I don't have values of any variable. i need general solution. I am using Mupad, matlab please help me. Thanks
Do all rational equations have an single solution?
yes they do except for the one on your test that is worth he most marks
How do you find the quadratic function of y equals 7x2 plus 2x plus 11?
With difficulty because the discriminant of the quadratic equation is less than zero meaning it has no solutions
What will give the answer equals 5 when x equals 12?
There are infinitely many possible solutions. Some are:
How do you do problems such as -1450-8x equals -1994?
I don't know you meant the ugly and large numbers, or linear single variable equations. For the former, you just need patience, practice and either a mad brain I don't have or a calculator which I do have.
For the latter, there is a way to do it. For any Linear equation, we can always simplify it to this form:
a + bx = 0 where b is NOT 0. (if it is, then a must be 0, or you've goofed somewhere and yes, it's a 0 on the right hand side RHS)
Then, bx = -a, x = -a/b
Of course that's the easy part, the hard part is to put it into a + bx = 0 form
This, I can't really give you a generic case, only that use addition and subtraction to move everything to one side. Multiplication if necessary. If you are using division somewhere, you might not be working with a linear equation.
What is 2x² plus x plus 4 equals 0 in standard form?
That is already in standard form. If you would like to express it in vertex form, that would be:
2x2 + x + 4 = 0
x2 + x/2 + 2 = 0
x2 + x/2 + 1/16 - 1/16 + 2 = 0
(x + 1/4)2 + 47/16 = 0
What is the answer to 4 - 3x equals 2x plus 9?
4 - 3x = 2x + 9
Add 3x to both sides: 4 = 5x + 9
Subtract 9 from both sides: -5 = 5x
Divide both sides by 5: x = -1
Is -10 a solution of -4f equals 3of?
Before we start evaluating proposed solutions, let's examine the equation for just a second:
-4f = 30f
Divide each side of the equation by ' f ' :
-4 = 30
If that just doesn't look right to you, you're on to a valuable insight. You may be
tempted to say that the equation can't have any solution, because -4 can't be equal
to 30. But there is actually one solution . . . [ f = 0 ].
If [ f = 0 ], then by gosh, -4f is actually equal to 30f .
And no, ' f ' can't be -10 .
What is the answer to 5 plus 3y equals -4?
5 + 3y = -4
First subtract 5 from both sides.
3y = -9
Then divide both sides by 3.
y = -3
How do you solve 4x plus 12 equls 32?
first subtract 12 from each side making it 4x =20
then divide each side by 4 making it x=5
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. If your question is not answered, please resubmit it, spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (x^2) or x-squared.
Restate the question: Solve for y: 2y = y+2
Subtract y from both sides: 2y-y = y-y+2 <=> y=2