Calculus

A quadrilateral with one pair of parallel sides is a trapezoid.

Yes, that is correct.

y=-4

It would be an imaginary number (one that cannot exist). For example the square root of a negative number.

X+2X2+4= just that. can't be simplified.

however...

X+2X+4= 3X+4

errr, is that what you meant?

y is increased by 7

2 decillion

Whatever you want it to be. In mathematics, letters are used for "variables", placeholders for a number which is not specified. Sometimes you are supposed to find a value of "y" so that a certain equation is true. For example, if y + 5 = 8, the only correct value for y is 3. In another equation, "y" may have a different value.

2(-2)-3y=6 which is equal to -4 -3y = 6 which is equal to -3y = 10 which is equal to y = -(10 / 3) = -3.333...

here for least value X=2,y=3

hence 2(3)-3(2)=0


=0

3x - 12 = -2x + 23

5x = 35 so x = 7

x=-0.7

The diagonal line collapses into a single point on that line.

Change the '5' to a smaller number.

z = 2

Factorised as (z - 2)(z - 2) = 0

Addition is commutative

If you mean Microsoft's backup file extension, it's function is to make PCs and Macs even more incompatible, thus putting more money into Bill Gates' pocket.

are you sure from this equation ?

x^2 + 9x + 11

____________ = zero

x + 7

or there is no zero ??

please be sure from the x^2 + 9x + 11 ???

The result obtain from the equation 4 plus -1 -21 is -18.

(956 - 830) x (908 x 291 + 598) =

(126) x (264228 + 598) = 33368076

Y. B. Mokashi has written:

'Prakshobha'

The answer is the infinite set of coordinates, each of which represents a point of the line given by the equation.

-x -2 = 2

so -x = 2+2 = 4

and so x = -4

The required condition is a*b ≠ 0. That is equivalent to the requirement that neither a nor b is 0.