Probability

there is a 1 to 5 probablilty that you will roll the sum of 6 with two dice.

Assuming then that there are 100 numbers, 1-100, the probability of the number 23 being randomly picked out of 100 is: 1/100 or 0.01.

The answer is 1/3. There are six possible outcomes (1 to 6) of which two (3 or 4) are favourable so the probability is 2/6 or 1/3. In general, if A and B are two events, then Pr (A or B) = Pr(A) + Pr(B0 - Pr(A and B) [the last bit is because you are double counting those events] Here Pr(A) = Pr(3) = 1/6, Pr(B) = Pr(4) = 1/6 and Pr(A and B) = Pr(3 and 4 - simultaneously) = 0 So Pr(3 or 4) = 1/6 + 1/6 + 0 = 1/3

The sample space for tossing 2 coins is (H = Heads & T = Tails): HH, HT, TH, TT

Probability of not blue is the probability of white. The probability of white is 11/(11+21) or 11/32.

To roll a 7, it doesn't matter what your first die rolls at, as every number on the die has a complement that will add up to 7. This means that your odds on rolling 7 are actually your odds on rolling the appropriate number on the second die. ie. 1/6. No matter what your first die is, the second can potentially give you a number that brings the total to 7.

To roll an 11 however, your odds are not as high. This is because you must roll a five and a six to hit 11. Your first die can be either of the two, but your second die must be it's complement. In this case then, your odds are 2/6 * 1/6, or 1/18.

The standard normal distribution is a normal distribution with mean 0 and variance 1.

We can write the sample space for 3 children as follows (b=boy, g=girl). bbb gbb bbg gbg bgb ggg bgg ggb The sample space is 8; each has a probability of 1/8. From above, you can see 3 instances that have 1 boy; bgg, gbg & ggb. Therefore, add 1/8 + 1/8 + 1/8 = 3/8 probability one boy having three children.

A discrete probability distribution is defined over a set value (such as a value of 1 or 2 or 3, etc). A continuous probability distribution is defined over an infinite number of points (such as all values between 1 and 3, inclusive).

There are 6 possible outcome when rolling a die. Of those, 3,4,5, and 6 are greater than 2. That means 4/6 odd of getting a number greater than 2. But 4/6 is the same as 2/3 or 66.67% Also, some dice are different from the standard ones. Here is another answer someone had: 

well it depends........if it's a 1-5 die then there's only 3/5 chances which is 60% chance so you are higher likely to get more than 2 if its an 1-7 die then its about a percent that i don't know but the more-number of sides it has the more chance you get more than 2....hope you win at whatever you win or this helped on what ever you are doing

The probability of flipping a Head is the same as that for a Tail and is 1/2 or 50%. The probability of rolling a particular number on a die is 1/6 since there are 6 numbers. Combining these two probabilities (by multiplication) we have, as the combined probability 1/2 x 1/6 = 1/12 = 0.0833333333333333(the 3 recurs) which as a percentage is 8.33333333333%

With two flips of a coin you can get two heads, two tails, a head and a tail, or a tail and a head. There are a total of four different possible outcomes, and three of them have at least one head. That's 3 out of 4, or 3/4ths. It's also 0.75 which is the probability of getting at least one head with two flips of a coin. Note that as we use the term probability here, it is zero (no chance it can happen at all), or one (it must happen), or something in between. A probability appears in the form of a fraction or decimal, and has no units attached to it.

The probability of correct true & false question is 1/2 and the probability correct multiple choice (four answer) question is 1/4. We want the probability of correct, correct, and correct. Therefore the probability all 3 questions correct is 1/2 * 1/2 * 1/4 = 1/16.

To find the solution, describe the events that will allow the same color draws which are WW or BB or YY. Since replacement is not stated, without replacement is assumed. So, we need probability of WW, BB, and YY (added together) which are (2/12*1/11) + (4/12*3/11) + (6/12*5/11) or (2/132 + 12/132 + 30/132) or 44/132 or1/3.

The probability of a flipped coin landing heads or tails will always be 50% either way, no matter how many times you flip it.

Convert to Standard Normal Distribution the values of 1.22 & 8.78. Z = (8.78-5)/1.41 = 2.68; and Z = (1.22-5)/1.41 = -2.68. Find the area between 2.68 & -2.68 from Table. Area @ 2.68 = .9963; Area @ -2.68 = .0037. Take the difference in the areas and that is the solution. 0.9963 - 0.0037 = .9926 or 99.26% of the scores fall between 1.22 & 8.78.

This is a binomial probability distribution. The number of trials, n, equals 30; and the probability of success is p, which is 0.1. In this problem, you want the probability of at least 5, which is the complement of at most 4. We use the complement because we can subtract from 1 that probability and we will have the solution. The related link has the binomial probability distribution table which is cumulative. Per the table, at n=30, p=0.1 and x = 4; the probability is 0.825. Therefore the probability of at least 5 is 1 - 0.825 or 0.175.

Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.

In craps, the chance for rolling a 7 never changes. First roll, tenth roll - doesn't matter. The chance is always 6 out of 36 (or roughly 17%). The chance of rolling a 6 is always 5 out of 36 (or 20%). The chance of rolling an 8 is always 5 out of 36 (or 20%). The chance of hitting either a 6 or an 8 before hitting a 7 would be 10 to 6 (with the favor going towards hitting either the 6 or 8).

There are two ways to look at this problem; gender or person.

Gender (M=Male, F=Female); There is only one way and that is MFMFMFMFM.

By person, you have 9 places to fill. The first is 5 males could be placed there, the next 4 females could be placed there, the next 4 males can be placed there, the next 3 females can be placed there and so forth. So in this instance there are 5*4*4*3*3*2*2*1*1 = 2880 arrangements.

Another way is

just 5!*4!=2880.

Here 5! is for men and 4! for women.

ie. Men can be arranged in 5 ways and women can be arranged in 4 ways.

Non probability sampling is where the samples are not selected randomly.

If there are 5 piles and your consideration is 4 of the 5 piles, the fraction would be 4/5.

If we toss three coins 240 times, how many times can we expect the coins to have three tails showing?

Probability is the number of occurrences of a specific event divided by the total number of possible events. Suppose you took a multiple choice test with 4 possible answer's A, B, C, D. Only 1 of the 4 choices is correct; so the probability of correct is 1/4 and the probability of incorrect is 3/4. Most of the time the two probabilities will not be the same.

The probability of a fair coin to land head is 1/2. Since for 4 flips it must land heads each time, the probability of 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16.