Probability

queens and princes

First work out the probability of the first two coins being heads and then the last being tails. This is 1/2 x 1/2 x 1/2 which is 1/8

The next step is to find out how many different orders the coins can come in. In this case there are 3 possible orders (HHT, HTH, and THH). Multiply this by the above probability and you get 3/8. Therefore the probability of getting two heads and one tail is 3/8

On an unweighted die, regardless of how many successes you've had, your chance of rolling a five will be one in six.

The chance of you rolling a die 16 times and getting a five each time would be 1/616, or 0.00000000000035447042.

The chance of rolling a die 16 times and getting the same number (regardless of what that number is) each time, would be 1/615, or 0.00000000000212682249

Regardless of how slim that chance is though, your chance on the next roll will still be 1/6.

However, if this is meant as a "real world" question, then your chances of rolling the same number so many times in a row is so low that at that point, your odds would be much higher of there being something odd with the die, or with your experiment. At that point, it would be sensible to say that the odds are very good of rolling another 5, regardless of the math, as there seems to be another factor affecting your outcome.

It is 4*(1/2)4 = 4/16 = 1/4

(1/2)*(1/2)*(1/2)*(1/2)*(1/2)*(1/2) = 1/26 = 1/64

The easiest way to do this is to first calculate the probability of drawing spade/heart/club/diamond in order. This is 13/52 times 13/51 time 13/50 times 13/49. Note that each time there are 13 possible cards to choose from out of a shrinking deck. This probability comes out at 0.004396. The reason it's so small is that we haven't accounted for all the different ways you can draw the cards. You might draw the spades first, or the hearts first. There are 4x3x2x1 different orders the cards can come in. Multiply the probability by this and you get 0.1055

So the probability of having 1 card from each suit is 0.1055

it is when you put a lot of effort into deviating the numbers from the the other numbers- with effort. I am number 2 and I do not like number 4.. I will deviate myself from it ... 222222222222 and then 123 (just to make it excited) and go

12356789 . HA.

1

depends what is the question asking

The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.

When the event of interest is a cumulative event.

For example, to find the probability of getting three Heads in 8 tosses of a fair coin you would use the regular binomial distribution. But to find the probability of up to 3 Heads you would use the cumulative distribution.

This is because

Prob("up to 3") = Prob(0 or 1 or 2 or 3) = Prob(0) + Prob(1) + Prob(2) + Prob(3) since these are mutually exclusive.

Likely means the same as probable and probable refers to the probability that something might happen,

Probability is measured using a scale of probability from zero to one.

Zero means that the event will definitely not happen whereas a probability of 1 means that the event is certain to happen, Similarly a probability of 0.5 means that the event is just as likely not to happen as to happen.

What is the probability that you could swim the Atlantic unaided? Zero

What is the probability that a bird will die? One

What is the probability that I can throw a 1 with a dice? 1 out of 6 = 0.1666666.......

What is the probability that I can toss a "heads" with a coin? 50% = 0.5 = one half

The probability of drawing a red two from a standard deck of 52 cards is 2 in 52, or about 0.03846.

The probability of rolling an odd number of a standard die is 3 in 6, or 1 in 2, or 0.5.

A card is drawn from a standard deck of playing cards. what is the probability that a spade and a heart is selected?

There are 2 of the threes that meet your condition.

The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.

If this is the only information you have, the answer would be somewhere around 125. Usually, you would find the third quartile by first finding the median. Then find the median of all of the numbers between the median and the largest number, which is the third quartile.

In a standard deck of 52 cards, there are 13 red cards and four queens. Since one of the red cards is also a queen, there are 16 cards that are either red or a queen. The probability, then, of drawing a red card or a queen is 16 in 52, or 8 in 26, or 4 in 13, or about 0.3077.

There are 12 face cards in a standard deck of 52 cards; the jacks, queens, and kings of spades, diamonds, clubs, and hearts. The probability, then, of drawing a face card is 12 in 52, or 3 in 13, or about 0.2308.

Yes, except that if you know that the distribution is uniform there is little point in using the empirical rule.

50/50

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attendant