Probability

The mean absolute deviation is 28.5

Possible outcomes of a single dice are 6 ( 1,2,3,4,5,6)

So if 5 such dices are rolled then the number of possible outcomes are 6 mulitiplied by 6 five times.

6x6x6x6x6x6=46656 possible outcomes.

you can arrange 8 pictures 28 different ways

0% of a normal (of any) distribution falls between z 1.16 and z 1.16. 1.16 - 1.16 = 0.

It is not possible to determine the range since there is always the possibility that there are outliers. Also, there is no information about the skewness of the data. If the distribution is symmetric, there is a high probability (99.75%) that the values will lie within 3 standard deviations of the mean - that is between 40 and 160.

The sample space for tossing a coin twice is [HH, HT, TH, TT].

The z-score is a statistical test of significance to help you determine if you should accept or reject the null-hypothesis; whereas the p-value gives you the probability that you were wrong to reject the null-hypothesis. (The null-hypothesis proposes that NO statistical significance exists in a set of observations).

The possible outcomes of a single dice is 6 ( 1,2,3,4,5, 6).

If two such dice are rolled the possible outcomes are 6 multiplied by 6, that is 36 outcomes. ((1,1),(1,2)...(2,1),(2,2).....(6,4),(6,5),(6,6))

One standard deviation for one side will be 34% of data. So within 1 std. dev. to both sides will be 68% (approximately) .the data falls outside 1 standard deviation of the mean will be 1.00 - 0.68 = 0.32 (32 %)

The probability of drawing a 4, 5, 6, 7, or 8 of spades is 5 in 52. The probability of not drawing a 4, 5, 6, 7, or 8 of spades, therefore, is (52-5) in 52, or 47 in 52, or about 0.9038.

Since there are 10 odd numbers (1, 3, 5, 7, 9, 11, 13, 15, 17, 19) in the 20 numbers (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20), the probability of picking an odd number in a random sample is 10 in 20, or 1 in 2, or 0.5.

The Poisson distribution with parameter np will be a good approximation for the binomial distribution with parameters n and p when n is large and p is small. For more details See related link below

The expected outcome is the sum of (each possible occurrence times the probability of that occurrence).

For example, the expected outcome of rolling one die is:

1 * 1/6 + 2 * 1/6 + 3 * 1/6 + 4 * 1/6 + 5 * 1/6 + 6 * 1/6 = 3.5.

The probability of this is based heavily on whether or not said best friend is even in the class. If both are in, it's a 1/870 chance.Ê

12 because there are 12 months and no one in the room has a birthday in the same month

It depends what you consider favorable.

There are 6 possible outcomes of a single roll of a 6-sided die.

the mean

Spades is the strongest suit in many card games.

almost

4 and twenty blackbirds baked in a pie.

The probability is 0.0322

50

* * * * *

z = -0.67449 to z = +0.67449

The GCF is 20x.