Probability

The probability of drawing an Ace from a standard deck of 52 cards is 4 in 52, or 1 in 13, or about 0.07692.

The probability of drawing a court card (a jack, queen, or king) from a standard deck of 52 cards is 12 in 52, or 3 in 13, or about 0.2308.

If you count the ace as a court card, then the probability is 16 in 52, or 4 in 13, or about 0.3077.

There are 13 diamonds in a 52-card deck

so the probability to get a diamond is 13/52=1/4=0.25

Half the cards in a standard pack are black.

Therefore the probability of drawing a black card is 1/2.

Half the sides of a coin are "heads" so again the probability is 1/2.

Therefore the probability you will both draw a black card and flip heads = 1/2 * 1/2 = 1/4.

There are 13 diamonds. Three cards are dealt. The probability of all of them being diamond is (13/52)(12/51)(11/50) = 1716/132600 = 11/850

No, a probability is a number between 0 (included) and 1 (included)

The probability is 1.

It is always raining - any time of the day or night, any day of the year - somewhere on Earth.

A number of trials, each of which has only two outcomes: these are usually termed "success" and "failure". The trials must be independent and the probability of success must remain constant.

8 numbers in total, 4 of those numbers are odd (1, 7, 5 and 3)

so 4/8

= 1/2

aka 50%, 0.5

Since the word MATH does not have any duplicated letters, the number of permutations of those letters is simply the number of permutations of 4 things taken 4 at a time, or 4 factorial, or 24.

the variance of the uniform distribution function is 1/12(square of(b-a)) and the mean is 1/2(a+b).

It depends on the size of the marbles and on the size of the paper bag, neither of which was given in the question. Please restate the question.

No.

We know there are 10! (ten factorial) permutations (that's about 3,628,800 permutations); however, we know that number includes repeated permutations, as there are 3 s', 3 t's and 2 i's. So we have to divide by the number of ways these can be written as individual permutations (if they were considered as unique elements), which are 3! (= 6), 3! and 2! (= 2) respectively.

So our final calculation would be 3628800 / (6 * 6 * 2) = 50400 unique permutations.

When the event of interest is a cumulative event.

For example, to find the probability of getting three Heads in 8 tosses of a fair coin you would use the regular binomial distribution. But to find the probability of up to 3 Heads you would use the cumulative distribution.

This is because

Prob("up to 3") = Prob(0 or 1 or 2 or 3) = Prob(0) + Prob(1) + Prob(2) + Prob(3) since these are mutually exclusive.

Likely means the same as probable and probable refers to the probability that something might happen,

Probability is measured using a scale of probability from zero to one.

Zero means that the event will definitely not happen whereas a probability of 1 means that the event is certain to happen, Similarly a probability of 0.5 means that the event is just as likely not to happen as to happen.

What is the probability that you could swim the Atlantic unaided? Zero

What is the probability that a bird will die? One

What is the probability that I can throw a 1 with a dice? 1 out of 6 = 0.1666666.......

What is the probability that I can toss a "heads" with a coin? 50% = 0.5 = one half

The probability of drawing a red two from a standard deck of 52 cards is 2 in 52, or about 0.03846.

The probability of rolling an odd number of a standard die is 3 in 6, or 1 in 2, or 0.5.

There are 13 clubs in a standard deck of 52 cards. The probability, then, of drawing club is 13 in 52, or 1 in 4, or 0.25.

A card is drawn from a standard deck of playing cards. what is the probability that a spade and a heart is selected?

There are 2 of the threes that meet your condition.

The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.

If this is the only information you have, the answer would be somewhere around 125. Usually, you would find the third quartile by first finding the median. Then find the median of all of the numbers between the median and the largest number, which is the third quartile.

In a standard deck of 52 cards, there are 13 red cards and four queens. Since one of the red cards is also a queen, there are 16 cards that are either red or a queen. The probability, then, of drawing a red card or a queen is 16 in 52, or 8 in 26, or 4 in 13, or about 0.3077.

There are 12 face cards in a standard deck of 52 cards; the jacks, queens, and kings of spades, diamonds, clubs, and hearts. The probability, then, of drawing a face card is 12 in 52, or 3 in 13, or about 0.2308.