Probability

No. The binomial distribution (discrete) or uniform distribution (discrete or continuous) are symmetrical but they are not normal. There are others.

When two dies are rolled, there are 36 different outcomes. (1,1),(1,2),....(6,6).

Let A denote the event of rolling doubles.

There are 6 doubles (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)

P(A) = 6/36=1/6

Let B denote the event that the product is 18.

Count how many of these outcomes give you a product of 18. Only (3,6) and (6,3) give you a product of 18.

P(B)=2/36=1/18

There are no events that give you a double and whose product is 18.

P(A or B) = P(A)+P(B)

P( double or 18) = 1/6+1/18 = 4/18 = 2/9

In a combination the order does not matter, so they are:

1 1 , 1 2 , 1 3 , 1 4 , 1 5 , 1 6

2 2 , 2 3 , 2 4 , 2 5 , 2 6

3 3 , 3 4 , 3 5 , 3 6

4 4 , 4 5 , 4 6

5 5 , 5 6

6 6

The odds of not drawing a 6 from a standard deck of 52 cards is 48 in 52, or about 0.9231.

It is not necessary that all symetric distribution may be normal.

The variance is standard deviation squared, or, in other terms, the standard deviation is the square root of the variance. In many cases, this means that the variance is bigger than the standard deviation - but not always, it depends on the specific values.

The probability of drawing three diamonds from a standard deck of 52 cards is (13 in 52) times (12 in 51) times (11 in 50), or 1716 in 132600, or about 0.01294.

When you throw a die, there are six possibilities. The probability of a number from 1 to 6 is 1/6. This is classical probability. Compare this with empirical probability. If you throw a die 100 times and obtain 30 sixes, the probability of obtaining a 6 is 30/100 or 0.3. Empirical probabilities change whereas classical probability doesn't.

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Don't know what "this" is, but all symmetric distributions are not normal. There are many distributions, discrete and continuous that are not normal. The uniform or binomial distributions are examples of discrete symmetric distibutions that are not normal. The uniform and the beta distribution with equal parameters are examples of a continuous distribution that is not normal.

The uniform distribution can be discrete or continuous.

If a 31-day month starts on a Friday, Saturday or Sunday it will have 5 Sundays; if not it will have 4. So the probability is 3/7.

The statement is false. The binomial distribution (discrete) or uniform distribution (discrete or continuous) are symmetrical but they are not normal. There are others.

The question is incorrect since the mean of 45 57 0 and 3 is not 30. And the value of 45 is 45, whatever its mean when combined with other numbers. Similarly, the value of 57 is 57, whatever its mean when combined with other numbers; etc.

The number of permutations of the letters EFFECTIVE is 9 factorial or 362,880. Since the letter E is repeated twice we need to divide that by 4, to get 90,720. Since the letter F is repeated once we need to divide that by 2, to get 45,360.

5/36

It can be.

it depends on the total number of marbles you have!

Yes, but only if every element in the data set is exactly the same. Therefore, very unlikely.

Theoretical is 50% Heads, 50% tails: 30-Heads, 30-Tails (theoretical)

Coin - 1/2 chance for either heads or tails

Die - 16 chance of landing on 1, 2, 3, 4, 5, or 6

The worth of word 13 cards of McDonalds Limited Edition 1993 Game Day collector cards can vary from person to person. There are people out there who may be looking for these. The best way to find out how much they are worth is to do a quick eBay look, and see if anyone is selling theirs, and how much. You can also find a private collector or appraiser to help you find the worth. It is hard to find the worth of a product without visually looking at it.

The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.

If you roll two dice, the following reuslts are possible:

2: 1+1

3: 1+2 , 2+1

4: 1+3, 2+2, 3+1

5: 1+4, 2+3, 3+2, 4+1

6: 1+5, 2+4, 3+3, 4+2, 5+1

7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1

8: 2+6, 3+5, 4+4, 5+3, 6+2

9: 3+6, 4+5, 5+4, 6+3

10: 4+6, 5+5, 6+4

11: 5+6, 6+5

12: 6+6

As you can see, the greatest number of permutations result in a total of 7. Its probability is 6/36 or 1/6.

Assuming of course that we are talking about cubic dice.

combinations that make 9:

6&3, 5&4, 4&5, 3&6. There are 4 combinations that make 9.

There are 36 possible combination of two dice.

So 4/36 is 1/9