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Probability
The probability of a certain event is a number expressing the likelihood that a specific event will occur, expressed as the ratio of the number of actual occurrences to the number of possible occurrences. In mathematics, it is a measure of how often an event will happen and is the basis of statistics.
14,643 Questions
What is the probability that an offspring will be black in the cross shown in punnett square B?
If you want to ask questions about something that is "shown", then I suggest that you make sure that there is something that is shown.
How many permutations are there for the letters in the word basketball?
BASKETBALL = 10 letters
B=2
A=2
S=1
K=1
E=1
T=1
L=2
Number of permutations = 10! /2!2!2!
= 10x9x8x7x6x5x4x3x2 / 2x2x2
=3,628,800 / 8
=453,600
What is the probability of drawing a red king from a deck of 52?
Probability of getting a King is 4/52 = 1/13. Having drawn the King, for it to be a Red King, the probability is 2/4 = 1/2. Hence the conditional probability is (1/13)x(1/2) = 1/26
What is the probability of spinning an even number all four times?
That depends on the numbers you can spin.
What is the probability of getting two prime numbers 1-10?
The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.
Is continuous distribution normal distribution?
le standard normal distribution is a normal distribution who has mean 0 and variance 1
What is the probability that a male offspring will have hemophilia?
Without any further information, the probability is between 0.0001 and 0.0002
What are the chances of picking a king and a diamond from a deck of cards?
the probability of picking a king from a deck of cards is 4/52,which is 1/13 because there are 4 kings. Which are king of heart, king of diamond,king of club and king of spade. And the probability of picking a diamond is 13/52,which is 1/4.
How do you find the probability of a spinner?
You find out how many choices there are in a spinner and then you take what it wants you to find the probability of and tur it into a fraction
For example:
You have a spinner with 4 triangles in it....2 are red and 2 are green,What is the probability of landing on a green triangle
2 out of 4
What are the odds against rolling a 4 in a fair die?
Well I'm supposing it's a 6 sided dye. Since there are 6 sides it's a 1 out of 6 chance or 16% chance that you would roll a 4.
The odds against rolling a 4, the complementary event, are 5 out of 6, a chance
of: 1 - 0.1666.. = 0.8333... ≈ 83.3%.
What is the probability of having exactly 2 boys out of 6 children?
The answer depends on whether the children are picked at random. If they were selected from inside a girls' school the probability should be quite close to 0. Likewise, if the children were picked inside a boys' school.
If six children are picked at random from a large group of children with an equal number of boys and girls, then the answer is
6C2*(1/2)6 = 15/32 = 0.47, approx.
How do you solve for probabilities in binomial distributions?
Suppose you have n trials of an experiment in which the probability of "success" in each trial is p. Then the probability of r successes is:
nCr*pr*(1-p)n-r for r = 0, 1, ... n.
nCr = n!/[r!*(n-r)!]
What is marginal probability function?
If f(x, y) is the joint probability distribution function of two random variables, X and Y, then the sum (or integral) of f(x, y) over all possible values of y is the marginal probability function of x.
The definition can be extended analogously to joint and marginal distribution functions of more than 2 variables.
5 marbles. 3 red marbles, 2 white marbles.
The probability of drawing a white marble is P(W) = 2/5 = 0.40
If the white marble is not returned to the rest of the marbles (no substitution), the
probability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.
The probability that the event of drawing first a white marble and without substitution
the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.
If the process of drawing the marbles is with substitution, the probability of the
second draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%
The probability that the event of first drawing a white marble and after returning the
marble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.
If there are 48 tacks, (15+5+20+8), you want to divide the number of one color over the total to find the percentage of that color out of the whole.
If there are 8 silver tacks, take 8 over 48, which equals .167.If there are 20 white tacks, take 20 over 48, which equals .4167
Now you know the percentage of silver out of the whole, and the percentage of white out of the whole.
To figure out the white and silver together, add them together!
White and Silver tacks make up about .583, or 58.3%
And that's your answer. You have a 58% chance of picking a white or silver tack from the box when picked at random.
If events A and B are statistically indepnedent, then the conditional probability of A, given that B has occurred is the same as the unconditional probability of A. In symbolic terms,
Prob(A|B) = Prob(A).
What is the p number of IS 2062 Gr B?
Dear All,
Before 2010 ( IS 2062 GR.B) is unassigned material,now it is revised P No.1 & G . NO. 1 as per ASME SEC IX 2011........
Regards
M.BALAJI
QA/QC ENGINEER
M/s. Toyo Engineering India Ltd.
The probability of obtaining 7 heads in eight flips of a coin is:
P(7H) = 8(1/2)8 = 0.03125 = 3.1%
What is the probability of getting a queen card in a deck of cards?
number of queen card = 4
number of cards in a deck of cards = 52
Probability of getting a queen card = 4/52 or 1/13
What sequence is most likely to result from flipping a fair coin 5 times?
Let x be the aleatory variable representing the number of heads appearing when
tossing a fair coin 5 times.
Using the 'Binomial Distribution': P(x) = 5Cx (1/2)5 , where 5Cx = 5!/[x!(5-x)!]
Then:
P(x=0) = (1/2)5 = 1/32
P(x=1) = 5(1/2)5 = 5/32
P(x=2) = 10(1/2)5 = 10/32
P(x=3) = 10(1/2)5 = 10/32
P(x=4) = 5(1/2)5 = 5/32
P(x=5) = (1/2)5 = 1/32
So the most likely combination of heads-tails to come out are; (3H,2T) and (2H,3T), with a probability of 10/32 (=5/16=0.3125=31.25%) either one.
For any one of these outcomes there are 10 different sequences, each of which has
a probability of happening of 1/32.
If one observes the list of results, it can be inferred that any head-tails sequence
that can be thought of in 5 tosses has the probability of turning out of 1/32.
What is the difference between the population mean and sample mean?
The population mean is the mean calculated over every member of the set of subjects being studied. It is usually not available and a survey is used to find an estimate for the population mean. The mean value of the variable in question, calculated from only the subjects included in the sample (or survey) is the sample mean. Provided some basic statistical requirements are met, the sample mean is a "good" estimate of the population mean.
