Probability

This is the answer.

2.576 sd

The probability of selecting a red card is 26 in 52 or 1 in 2. The probability of selecting an even card is 20 in 52 or 5 in 13. The probability, therefore, of selecting a red even card is 1 in 2 times 5 in 13 or 5 in 26.

z = -1.644853 (approx).

75%

The probability that it contains exactly 3 balls is 6/45 = 0.133... recurring.

If an event occurs in n trials out of N experiments than the experimental probability of that event is n/N.

You have not given any information about the shape and numbering of the dice nor how many are thrown each time. Without that information it is not possible to answer the question.

In general, you cannot. The answer depends on the shape of the spinner - how many sides it has and what numbers are on it.

1/4

2 possibilities: true or false

3 questions

2^3

2*2*2 = 8 ways

4 numbers: 1/74 = 0.000 061 035

7 numbers: 1/77 = 0.000 001 214

There are 4*4*3*2*1 = 96 such numbers.

If the question is asking if a continuous distribution can be converted to a discrete distribution, the answer is yes.

Your age has a continuous distribution but in most cases, the information is recorded and analysed as if it were the whole number of years - a discrete distribution.

Since the standard deviation is zero, the scores are all the same. And, since their mean is 10, they must all be 10.

6 x 5 x 4 x 3 x 2/2 = 360 distinct ways

Statistics is based on the theoretical foundation of probability.

The probability of rolling a six on either (or both) die is 11/36.

# of diamond card = 13

# of black 7 card = 2

P(diamond and black 7) = 13/52 * 2/51 = 1/4 * 2/51

Answer = 1/102

A representative sample is a randomly selected subset of the population.

The probability of getting tails in any one flip is 1/2, so 1/2 x 1/2 x 1/2 x 1/2 = 1/16, or 6.25%

120 ways, 5! (5 factorial)

for first place you have 5 candidates,

for second place you have 4 candidates,

for third place you have 3 candidates,

for fourth place you have 2 candidates,

for last place you have 1 candidates,

5 x 4 x 3 x 2 x 1 = 120 different ways

The probability that three F2 seeds chosen from Mendel's study group will have at least one yellow seed is 63/64. It would be very rare to get three green seeds.

just multiply them together 2*3=6

muffin-(coffee) OR (milk) OR (juice): three possibilities

toast- (coffee) OR (milk) OR (juice): three possibilities

6 total